Answer:
:)
Step-by-step explanation:
F(x) = 4x + 3
the domain: Df = R
g(x) = -2x + 5
the domain: Dg = R
Df = Dg therefore (f · g)(x) = f(x) · g(x)
f(5) = 4 · 5 + 3 = 20 + 3 = 23
g(5) = -2 · 5 + 5 = -10 + 5 = -5
(f · g)(5) = f(5) · g(5) = 23 · (-5) = -115
Answer:
h x 8
Step-by-step explanation:
when there is no sign in between that means to multiply
Answer:
Yes, it is possible. We already know that complex roots exist in conjugate pair but the case is true only when the equation has real coefficients. But on the other hand, if the equation has complex coefficients, then it is possible to attain one real and one complex root.
If you read this site Thoroughly you can fine the answer Hope this Helps! http://jwilson.coe.uga.edu/EMT668/EMAT6680.Folders/Barron/unit/Lesson%205/5.html
