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sleet_krkn [62]
3 years ago
14

Explain using two different methods why the function y equals 2x - 3 is linear

Mathematics
1 answer:
Katena32 [7]3 years ago
8 0
If you read this site Thoroughly you can fine the answer Hope this Helps! http://jwilson.coe.uga.edu/EMT668/EMAT6680.Folders/Barron/unit/Lesson%205/5.html 
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Noah applies two transformations to WXYZ so that the final vertices of the transformed
krok68 [10]

Answer:

ok

Step-by-step explanation:

4 0
3 years ago
How do I state the excluded values for this rational expression: 60x^3/12x
Stella [2.4K]

Answer:

5x^2

Step-by-step explanation:

12 can be taken out from the top and bottom then for the x you subtract

7 0
3 years ago
Let f(x)=5(x^2-3)+10. which statement must be true?
Maslowich
Find where the expression
x
−
5
x
2
−
25
x
-
5
x
2
-
25
is undefined.
x
=
−
5
,
x
=
5
x
=
-
5
,
x
=
5
Since
x
−
5
x
2
−
25
x
-
5
x
2
-
25
→
→
−
∞
-
∞
as
x
x
→
→
−
5
-
5
from the left and
x
−
5
x
2
−
25
x
-
5
x
2
-
25
→
→
∞
∞
as
x
x
→
→
−
5
-
5
from the right, then
x
=
−
5
x
=
-
5
is a vertical asymptote.
x
=
−
5
x
=
-
5
Consider the rational function
R
(
x
)
=
a
x
n
b
x
m
R
(
x
)
=
a
x
n
b
x
m
where
n
n
is the degree of the numerator and
m
m
is the degree of the denominator.
1. If
n
<
m
n
<
m
, then the x-axis,
y
=
0
y
=
0
, is the horizontal asymptote.
2. If
n
=
m
n
=
m
, then the horizontal asymptote is the line
y
=
a
b
y
=
a
b
.
3. If
n
>
m
n
>
m
, then there is no horizontal asymptote (there is an oblique asymptote).
Find
n
n
and
m
m
.
n
=
1
n
=
1
m
=
2
m
=
2
Since
n
<
m
n
<
m
, the x-axis,
y
=
0
y
=
0
, is the horizontal asymptote.
y
=
0
y
=
0
There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.
No Oblique Asymptotes
This is the set of all asymptotes.
Vertical Asymptotes:
x
=
−
5
x
=
-
5
Horizontal Asymptotes:
y
=
0
y
=
0
No Oblique Asymptotes
5 0
3 years ago
Please answer the last conversion !! 531 ms to s
Tcecarenko [31]

Answer:

0.531 s

Hope it helped u if yes mark me BRAINLIEST

5 0
3 years ago
Read 2 more answers
Suppose you randomly select a letter from BURGER AND STARBIRD. Imagine writing these letters on Ping-Pong balls – one letter per
TiliK225 [7]
First, count the total number of letters in <span>BURGER AND STARBIRD.
There are 17 letters.
Now count each type of letter you are interested in and divide by 17.

a) There are four R's, so the probability of pulling out an R is 4/17.

b) </span><span>There are two B's, so the probability of pulling out an B is 2/17.

c) Letters A through M appear in the first half of the alphabet.
These letters are from the first half of the alphabet:
</span><span>BGEADABID
There are 9 of them.
</span>The probability of pulling out a letter that appears in the first half of the alphabet is 9/17.

d) <span>These letters are vowels
</span><span>UEAAI
There are five vowels.
</span><span>The probability of pulling out a vowel is 5/17.</span>
8 0
3 years ago
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