Answer:
Fernando invested $ 5000 on the 5-year CD and $ 4000 on the 18-month CD.
Step-by-step explanation:
Since Fernando invested money in a 5-yr CD (certificate of deposit) that returned the equivalent of 3.3% simple interest, and the invested $ 1000 less in a 18-month CD that had a 2% simple interest return, if the total amount of interest from these investments was $ 945.00, to determine how much was invested in each CD the following calculation must be performed:
3.3 x 5 = 16.5
2 x 1.5 = 3
4000 x 0.165 + 3000 x 0.03 = 750
6000 x 0.165 + 5000 x 0.03 = 1140
5000 x 0.165 + 4000 x 0.03 = 945
Therefore, Fernando invested $ 5000 on the 5-year CD and $ 4000 on the 18-month CD.
#42.
14n - 32 = 22
add 32 to both sides
14n - 32 + 32 = 22 + 32
simplify
14n = 54
divide both sides by 14
14n/14 = 54/14
simplify
n = 3 12/14
n = 3 6/7 or n = 3.857
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)
moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g
Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05
N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
Answer:
Step-by-step explanation:
54.08
Answer: 0.92 pounds
Step-by-step explanation:
Roberto will make 11 pounds of fudge but wants to give it away as presents to 12 friends.
Each friend will therefore get;
= 11 pounds/ 12
= 0.92 pounds
