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3 years ago

At 2.15 pm and leaves at 4.45 pm on Thursday

Mathematics

1 answer:

bazaltina [42]3 years ago

6 0

Two hours and thirty minutes if that's the question

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Which equation, together with y = -1.5x + 3, makes a system with one solution?

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The answer to your problem would be 2Y +3x=6

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Number system study guide

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But there is no problem here

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What is the location of point R on the number line?<br> 14/5, 16/5, 18/5, 22/5

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Answer: 14/5

Step-by-step explanation:

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3 years ago

A grocery store recently sold a bag of peanuts for $0.76 and a bag of Pikachu's for $3.68 at the end of the day 50 bags of peanu

Setler [38]

Answer:

31 Pikachu bags were sold.

19 peanut bags were sold.

Step-by-step explanation:

Let's set up an equation of the total revenue of the day, where x is the number of Pikachu's sold.

We know that the number of Peanuts sold is 50-x (as the total needs to be 50)

We know that the total revenue is:

Number of Pikachus * Cost per Pikachus + Number of Peanuts * Cost per Peanuts

Using our definitions above:

Total Revenue = x * $3.68 + (50-x) * $0.76

We know that the revenue needs to be $128.52.

$128.52 = x * $3.68 + (50-x) * $0.76

Let's remove the $ signs.

128.52 = x * 3.68 + (50-x) * 0.76

Multiplying both 50 and -x with 0.76, "expanding" the parenthesis.

128.52 = x*3.68 + 50*0.76 - x*0.76

128.52 = x*3.68 + 38 - 0.76*x

Subtracting 38 from both sides

90.52 = 3.68*x - 0.76*x

We can simplify the right side.

90.52 = 2.92*x

We can divide both sides by 2.92:

31 = x

And flip it:

x = 31

So 31 Pikachus were sold (remember we claled that x), and as we know, the number of peanut bags sold is

50-x = 50-31 = 19

31 Pikachu bags were sold.

19 peanut bags were sold.

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3 years ago

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Part of the proceeds from a garage sale was $470 worth of $10 and $20 bills. If there were 14 more $10 bills than $20 bills, fin

Brums [2.3K]

There are 25 $10 bills and 11 $20 bills.

Step-by-step explanation:

Given,

Worth of proceeds from garage = $470

Let,

x be the number of $10 bills

y be the number of $20 bills.

According to given situation;

10x+20y=470 Eqn 1

x = y+14 Eqn 2

Putting value of x from Eqn 2 in Eqn 1

$10(y+14)+20y=470\\10y+140+20y=470\\30y=470-140\\30y=330$

Dividing both sides by 30

$\frac{30y}{30}=\frac{330}{30}\\y=11$

Putting y=11 in Eqn 2

$x=11+14\\x=25$

There are 25 $10 bills and 11 $20 bills.

Keywords: linear equation, substitution method

Learn more about linear equations at:

#LearnwithBrainly

5 0

3 years ago