Answer:
.
Step-by-step explanation:
It is given that a number, x, rounded to 2 significant figures is 1300.
It is possible if,
1. The value of x is greater than of equal to 1250 and less than or equal to 1300.
i.e., 
...(1)
2. The value of x is greater than of equal to 1300 and less than 1350.
i.e., 
...(2)
On combining (1) and (2), we get
1350 is not included in the error interval for x.
Interval notation is .
Therefore, the error interval for x is .
Answer:
f(-2) = -1
Step-by-step explanation:
-2 is x, so replace x as -2 into the equation
f (-2) = 2(-2) + 3
f (-2) = -4 + 3
f (-2) = -1
Answer:
The system of inequalities that represents this situation is:
x+y≥10
6x+4y≤50
Step-by-step explanation:
As the statement says that Laura wants to provide one party favor per person to at least 10 guests, the first inequality would indicate that the number of stuffed animals plus the number of toy trucks should be equal or greater than 10:
x+y≥10
Also, the statement indicates that miniature stuffed animals cost $6.00 each and the toy trucks cost $4.00 each and that Laura has $50. From this, you would have an inequality that indicates that 6 for the number of miniature stuffed animals and 4 for the number of toy trucks would be equal or less than 50:
6x+4y≤50
The answer is that the system of inequalities that represents this situation is:
x+y≥10
6x+4y≤50
This set notation really seems the hard way to exclude a single value. Anyway...
The domain doesn't include where the denominator is zero, 4x + 7 = 0,
x = -7/4
The range doesn't include the asymptotic value, which is
y=2x/4x = 1/2
So we need domain x ≠ -7/4 and range y ≠ 1/2
Answer: First choice
