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g100num [7]
3 years ago
5

Please help me I need help

Mathematics
1 answer:
MariettaO [177]3 years ago
8 0
The collect 19 boxes by the end of everyday.
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Rebecca and dan are biking in a national park for three days they rode 5 3/4 hours the first day and 6 4/5 hours the second day
AfilCa [17]

Answer:

Rebecca and Dan need to ride 7\frac{9}{20}\ hrs. on the third day in order to achieve goal of biking.

Step-by-step explanation:

Given:

Goal of Total number of hours of biking in park =20 hours.

Number of hours rode on first day = 5\frac34 \ hrs.

So we will convert mixed fraction into Improper fraction.

Now we can say that;

To Convert mixed fraction into Improper fraction multiply the whole number part by the fraction's denominator and then add that to the numerator,then write the result on top of the denominator.

5\frac34 \ hrs. can be Rewritten as \frac{23}{4}\ hrs

Number of hours rode on first day = \frac{23}{4}\ hrs

Also Given:

Number of hours rode on second day = 6\frac45 \ hrs

6\frac45 \ hrs can be Rewritten as \frac{34}{5}\ hrs.

Number of hours rode on second day = \frac{34}{5}\ hrs.

We need to find Number of hours she need to ride on third day in order to achieve the goal.

Solution:

Now we can say that;

Number of hours she need to ride on third day can be calculated by subtracting Number of hours rode on first day and Number of hours rode on second day from the Goal of Total number of hours of biking in park.

framing in equation form we get;

Number of hours she need to ride on third day = 20-\frac{23}{4}-\frac{34}{5}

Now we will use LCM to make the denominators common we get;

Number of hours she need to ride on third day = \frac{20\times20}{20}-\frac{23\times5}{4\times5}-\frac{34\times4}{5\times4}= \frac{400}{20}-\frac{115}{20}-\frac{136}{20}

Now denominators are common so we will solve the numerator we get;

Number of hours she need to ride on third day =\frac{400-115-136}{20}=\frac{149}{20}\ hrs \ \ Or \ \ 7\frac{9}{20}\ hrs.

Hence Rebecca and Dan need to ride 7\frac{9}{20}\ hrs. on the third day in order to achieve goal of biking.

3 0
3 years ago
(b) In a company, out of 20 candidates 14 men and 6 women apply for two vacancies. What is the probability that (1) both men are
Doss [256]

i hope my answer helps you and you will give me the best answer

5 0
2 years ago
A population of bacteria is introduced into a culture. the number of bacteria P can be modeled by P=500(1+4t/(50+t^2 )) where t
Dennis_Churaev [7]
P(t)=500(1+4t/(50+t^2 ))

P'(t) = 500 [(50+t^2).4 - 4t.2t]/(50+t^2)^2

  by the quotient rule

 500 (-4t^2 + 200)/(t^2 + 50)^2

Hence

 P'(2) = 500 . (-16 + 200)/54^2 ~= 31.6
6 0
3 years ago
For a statistics class project, a college student randomly samples 75 men who exercise at a gym regularly and 68 women who exerc
pav-90 [236]

Answer:

Step-by-step explanation:

The record of the statistics and the summary statistics which are the missing files in the question are attached below.

From the given information:

The null hypothesis and the alternative hypothesis can be represented by :

\mathbf{H_o:} There is no difference between the average time  spend by men and women at gym each week

\mathbf{H_i:} The average time  spend by men is greater than the average time spend by women at the gym each week

From the summary statistics in the attached file below:

The p-value = 0.3253

Level of significance = 5% = 0.05

Therefore; it is obvious that the p-value is greater than the level of significance  i.e (0.3253 > 0.05)

Hence; there is no enough evidence to reject the null hypothesis

CONCLUSION: We conclude that the mean number of minutes exercised per week is larger for men than women at the  this gym.

6 0
3 years ago
Mr. Huyck needs 8 gallons of punch for the school dance. How many<br> quarts of punch would he need?
koban [17]
32 bc eight times four equals 32
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