Hi, It is well simples:
The distance between two points is :
d( A, B) = √[ (xb - xa)^2+(yb - ya)^2+(zb - za)^2]
Then,
A = (xa, ya, za )
B = (xb , yb , zb)
We know:
A = ( 2 ,0 ,-2)
And,
B = (5 , -4 , 6)
___________
xb - xa = 5-2 <=> 3
yb - ya = -4 - 0 <=> -4
zb - za = 6 - (-2) <=> 8
Then us stay:
d( A, B) = √[ (3)^2 + (-4)^2+(8)^2]
= √( 9 + 16 + 64)
= √( 25 + 64)
= √(89)
<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
<em />
Hence, BC=DC proved.
Answer: there you go
Step-by-step explanation: That is the answer
Answer:
E
Step-by-step explanation:
Total: 20 blocks
Green: 8
8/20
Please mark as Brainliest! :)
Have a nice day.
Answer:
(3x - 1)(4x - 3)
Step-by-step explanation:
separating terms it will look like this
(3x - 1)(4x - 3)
when multiple each numbers you will see it will form up as 12x^2 -13x + 3
