All categories

3 years ago

Which rays are part of line BE? Ac and O AB and AĖ AC and AB AB and F

Mathematics

1 answer:

Zanzabum3 years ago

3 0

Answer:

We are given a diagram with different rays and lines.

Note: A line can be extend more and more upto infinitely length from both of the ends but a ray can be extend from end only.

We need to find the rays for the line BE.

We can see BE line has a point A in between line.

So, we can name the rays formed with end point A as AB and AE.

Therefore, AB and AE rays are part of line BE.

So, the correct option is 2nd option :

AB and AE.

Step-by-step explanation:

You might be interested in

There is a number three times the number -6 is equal to 45 find the number

Oduvanchick [21]

Answer:

6+ 45 = 500 #!_ djdjbdkeknf

4 0

3 years ago

Read 2 more answers

Can someone help me pls

Snezhnost [94]

Answer:

1; 180

2: 180

3:155

Step-by-step explanation:

7 0

3 years ago

Translate the sentence into an equation or formula. Seven less than the sum of p and t is as much as 6.

Virty [35]

(P+T)-7 = 6. 7 less than, meaning taking away 7 from the sum of (P + T) is as much as / equal to 6

4 0

1 year ago

An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s

Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, $s=120\ ft/s$

The height 'h' of the debris above the ground is given as:

$h(t)=-16t^2+120t$

As per question, $h(t)=56\ ft$ . Therefore,

$56=-16t^2+120t$

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

$-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0$

Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$