I would recommend "Introduction to Linear Algebra," by Gilbert Strang. It is a compact but very helpful textbook reference written by a well-known MIT professor. There is a corresponding online MIT course that is free, so that's a bonus. I am currently using it to study linear algebra with no class or previous experience, and I think it does a solid job of explaining things. Each section in the book has a set of questions for you to work through, and answers to selected questions appear in an appendix at the end of the book.
Hope this helps!
Do you mean millions? If so, please write 4,110,000, which is in terms of millions and is in standard form. Otherwise, ensure that you have copied down this problem correctly.
Answer:
1.1 gigabytes
Step-by-step explanation:
Let us represent:
The number of gigabytes = g
Under his cell phone plan, Owen pays a flat cost of $67.50 per month and $4 per gigabyte. He wants to keep his bill at $71.90 per month.
The Equation is given as:
$71.90 = $67.50 + $4 × g
71.90 = 67.50 + 4g
71.90 - 67.50 = 4g
4.4 = 4g
x = 4.4/4
x = 1.1 gigabytes
Therefore, the number of gigabytes of data Owen can use while staying within his budget is 1.1 gigabytes
The solution of the system can be x - 3y = 4 only if both the equations can be simplified to x - 3y = 4.
This will mean that both the equations will result in the same line which is x - 3y = 4 and thus have infinitely many solutions.
Second equation is:
Qx - 6y = 8
Taking 2 common we get:
(Q/2)x - 3y = 4
Comparing this equation to x- 3y = 4, we can say that
Q/2 = 1
So,
Q = 2
Therefore, the second equation will be:
2x - 6y = 8
