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Phantasy [73]
3 years ago
13

Use the limit definition of the derivative to find the slope of the tangent line to the curve

Mathematics
1 answer:
ale4655 [162]3 years ago
3 0

Answer:

\displaystyle f'(4) = 63

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Distributive Property

<u>Algebra I</u>

  • Expand by FOIL (First Outside Inside Last)
  • Factoring
  • Function Notation
  • Terms/Coefficients

<u>Calculus</u>

Derivatives

The definition of a derivative is the slope of the tangent line.

Limit Definition of a Derivative: \displaystyle f'(x)= \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}  

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 7x² + 7x + 3

Slope of tangent line at x = 4

<u>Step 2: Differentiate</u>

  1. Substitute in function [Limit Definition of a Derivative]:                              \displaystyle f'(x)= \lim_{h \to 0} \frac{[7(x + h)^2 + 7(x + h) + 3]-(7x^2 + 7x + 3)}{h}
  2. [Limit - Fraction] Expand [FOIL]:                                                                    \displaystyle f'(x)= \lim_{h \to 0} \frac{[7(x^2 + 2xh + h^2) + 7(x + h) + 3]-(7x^2 + 7x + 3)}{h}
  3. [Limit - Fraction] Distribute:                                                                            \displaystyle f'(x)= \lim_{h \to 0} \frac{[7x^2 + 14xh + 7h^2 + 7x + 7h + 3] - 7x^2 - 7x - 3}{h}
  4. [Limit - Fraction] Combine like terms (x²):                                                     \displaystyle f'(x)= \lim_{h \to 0} \frac{14xh + 7h^2 + 7x + 7h + 3 - 7x - 3}{h}
  5. [Limit - Fraction] Combine like terms (x):                                                      \displaystyle f'(x)= \lim_{h \to 0} \frac{14xh + 7h^2 + 7h + 3 - 3}{h}
  6. [Limit - Fraction] Combine like terms:                                                           \displaystyle f'(x)= \lim_{h \to 0} \frac{14xh + 7h^2 + 7h}{h}
  7. [Limit - Fraction] Factor:                                                                                 \displaystyle f'(x)= \lim_{h \to 0} \frac{h(14x + 7h + 7)}{h}
  8. [Limit - Fraction] Simplify:                                                                               \displaystyle f'(x)= \lim_{h \to 0} 14x + 7h + 7
  9. [Limit] Evaluate:                                                                                                 \displaystyle f'(x) = 14x + 7

<u>Step 3: Find Slope</u>

  1. Substitute in <em>x</em>:                                                                                                \displaystyle f'(4) = 14(4) + 7
  2. Multiply:                                                                                                           \displaystyle f'(4) = 56 + 7
  3. Add:                                                                                                                  \displaystyle f'(4) = 63

This means that the slope of the tangent line at x = 4 is equal to 63.

Hope this helps!

Topic: Calculus AB/1

Unit: Chapter 2 - Definition of a Derivative

(College Calculus 10e)

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Answer:

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Step-by-step explanation:

so, if f (x) equals 13, you replace the x in the equation to 13.

f(x)=-2x+5

f(x)=-2(13)+5

f(x)=26+5

f(x)=31

I believe 41 would be your answer. Hope this is right and it helped!

4 0
3 years ago
6/15=2/c HOW TO SOLVE THIS PROBLEM
Maslowich
The answer is 5. 
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Arada [10]

Answer:

The answer will be 0.666 repeating.

Step-by-step explanation:

4/6 = 0.6666.....

Since the numerator (4) is smalled than the denominator(6) the answer will be a decimal.

when 4 is divided by 6 it will gives us 0.66666667....

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On Monday, a company stock closed at a price of $30.80 per share. On Tuesday, it increased by $1.20 per share. On Wednesday, it
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If I did this correctly, the answer should be 2.72. Monday's stock price is given to you already, 30.80. To find Tuesday's, you'd add 1.20 to the already existing 30.80, that totals to 32. To find the number for Wednesday you would have to get the percentage and move the decimal so you can multiply it, it should end at .0625. You then get that number and multiply it by 32 because it was Tuesday's amount. From that you should get 2. You then subtract the 2 and the total for Wednesday is 30. You do the same for Thursday, you get the already existing number, 30, and multiply it by .04. That should end in 1.2. You then subtract that 1.2 and you should get 28.8 as your answer for Thursday. For Friday, the steps repeat. You take the 28.8 and multiply it by .025. That should equal to .72. You now subtract that .72 from Thursday's amount and should be left with 28.08 for Friday. Now that all the numbers are known, take the numbers for Monday and for Friday and then subtract them. (30.80-28.08) It should equal to 2.72.
7 0
3 years ago
ACTIVITY 1
aleksklad [387]

Answer:

Question A:

1. 1/2  = 0.5 (Terminating)

2. 5/6  = 0.833333.. (Repeating)

3. 21/3 = 1.6666666.. (Repeating)

Question B:

1. 0.6  = 3/5

2. 1.25  = 5/4 = 1 1/4

3. 0.125 = 1/8

Step-by-step explanation:

A. Write the fraction or mixed number as a terminating or repeating decimal.

In order to convert a fraction into decimal, the numerator has to be divided by denominator.

1. 1/2

The answer is: 0.5 which is a terminating decimal.

2. 5/6

The answer is: 0.833333.. which is a repeating decimal.

3. 2 1/3 (assuming the question is this)

2\frac{1}{3} = \frac{7}{6} = 1.6666666..

The answer is 1.6666666.. which is a repeating decimal.

B. Write the terminating decimal as fraction or mixed number i n simplest form.

1. 0.6

0.6 = \frac{6}{10} = \frac{3}{5}

2. 1.25

1.25 = \frac{125}{100} = \frac{5}{4} = 1\frac{1}{4}

3. 0.125

0.125 = \frac{125}{1000} = \frac{5}{40} = \frac{1}{8}

Hence,

Question A:

1. 1/2  = 0.5 (Terminating)

2. 5/6  = 0.833333.. (Repeating)

3. 21/3 = 1.6666666.. (Repeating)

Question B:

1. 0.6  = 3/5

2. 1.25  = 5/4 = 1 1/4

3. 0.125 = 1/8

7 0
3 years ago
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