Answer:
D 0.00000256
Step-by-step explanation:

Answer:
With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error:

For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is
We need a sample size of at least n, in which n is found M = 0.04.







With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.
Answer:
maby c
Step-by-step explanation:
tell me if this helps
You need to find the percent of the 125 surveyed students to find the number of estimated students that like pizza.
58/125 = .464 or 46.4%
1500*.464 = 696 students like pizza.
Hope this helps!
The equation is actually
circle area = PI * radius^2
radius = square root (area / PI)