Which value would not be part of the domain of the inverse of the given relation?

If the function f(x)=-1/2x-7 were graphed, which of the following is true? hurry I have 10 minutes

jeka94

WE NEED ANSWER CHOICES

4 0

3 years ago

What is 102% as a fraction

scZoUnD [109]

102% as a fraction would be 102/100, because a percent is by the one hundreds, and you can have a fraction be by hundreds. You can reduce the fraction by dividing it by 2, which equals 51/50. Another example, to clarify, is to make 41% a fraction, and decimal. Once again a percent is base 100, so the fraction would be 41/100, then to make it a decimal, you would put a decimal point in front of the 41, to make it .41. Hope I helped, and if you don't understand, tell me and I will try to make it better.

5 0

3 years ago

Read 2 more answers

Which point on the line number line represntes -1/3

OverLord2011 [107]

Answer:

Point C

Happy Holidays!

5 0

3 years ago

Read 2 more answers

Solve for the missing side to the nearest tenth.<br> 16<br> 30<br> X =

Mrrafil [7]

Answer: x=32

Step-by-step explanation:

Because a triangle is 180°, the missing angle in the triangle would be 60°.

Because of the 30°-60°-90° angles theorem, The side opposite 90° is double the side opposite 30°, which means that x=32.

3 0

3 years ago

Many high school students take the AP tests in different subject areas. In 2007, of the 144,796 students who took the biology ex

Nataly [62]

Answer:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion female for Biology

$\hat p_A =\frac{84199}{144796}=0.582$ represent the estimated proportion female for biology

$n_A=144796$ is the sample size for A

$p_B$ represent the real population proportion female for calculus AB

$\hat p_B =\frac{102598}{211693}=0.485$ represent the estimated proportion female for Calculus AB

$n_B=211693$ is the sample size required for B

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

5 0

3 years ago