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sleet_krkn [62]
4 years ago
15

Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution.

Mathematics
2 answers:
Darina [25.2K]4 years ago
4 0

Answer:

There is no solution for the given radical equation.

x = 225/16 is an extraneous solution.

Step-by-step explanation:

The given equation is  

Add 3 to both sides of the equation

Squaring both sides

Divide both sides by 16

Substituting back the value of x in original equation to check the extraneous solution.

 

Since -18≠ 12. Hence, the value of x does not satisfy the equation.

Therefore, x = 225/16 is an extraneous solution.

Step-by-step explanation:

zhannawk [14.2K]4 years ago
4 0

Answer:

yes i do have the answer i wat you to up the points

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<u>Step-by-step explanation:</u>

We have, the graph of f(x)= 2^{x} , on replacing f(x) by f(x-3) we get:

f(x-3)= 2^{x-3} = \frac{2^{x}}{2^{3}} = \frac{1}{8} 2^{x} = \frac{1}{8} f(x).Below shown are the images for graph of f(x) and f(x-3). Both are functions are exponential , and so having exponential graph but f(x-3) is compressed by a factor of  \frac{1}{8} horizontally . Domain and range of both functions are same i.e. F(x) & f(x-3) domain & range are same , just difference in graph : f(x-3) = \frac{1}{8} f(x).

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Step-by-step explanation:

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