All categories

3 years ago

Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution.

Mathematics

2 answers:

Darina [25.2K]3 years ago

4 0

Answer:

There is no solution for the given radical equation.

x = 225/16 is an extraneous solution.

Step-by-step explanation:

The given equation is

Add 3 to both sides of the equation

Squaring both sides

Divide both sides by 16

Substituting back the value of x in original equation to check the extraneous solution.

Since -18≠ 12. Hence, the value of x does not satisfy the equation.

Therefore, x = 225/16 is an extraneous solution.

Step-by-step explanation:

zhannawk [14.2K]3 years ago

4 0

Answer:

yes i do have the answer i wat you to up the points

You might be interested in

Please help!!!!

vfiekz [6]

I solved this problem by setting 240/80 equal to x/100 . Once you set them equal to each other, multiply 240 and 100 and divide the product by 80 and you get 300.

3 0

3 years ago

The volume of cylinder is 448 pie cm cube and height 7 cm find its radius

Verizon [17]

Answer:

$r =\bf 8 \space\ cm$

Step-by-step explanation:

The formula for volume of a cylinder is as follows:

$\boxed{Volume = \pi r^2 h}$

where:

• r = radius (? cm)

• h = height (7 cm).

Substituting the values into the formula:
$448 \pi = \pi \times r^2 \times 7$

Now solve for $r$ :

⇒ $r^2 = \frac{448 \pi }{\pi \times 7}$

⇒ $r = \sqrt{64}$

⇒ $r =\bf 8 \space\ cm$

8 0

2 years ago

Read 2 more answers

Use the Ratio Test to determine whether the series is convergent or divergent. [infinity] n! 112n n = 1 Identify an. Correct: Yo

MakcuM [25]

Answer:

Step-by-step explanation:

Recall that the ratio test is stated as follows:

Given a series of the form $\sum_{n=1}^{\infty} a_n let L=\lim_{n\to \infty}\left|\frac{a_{n+1}}{a_n}\right|$

If L<1, then the series converge absolutely, if L>1, then the series diverge. If L fails to exist or L=1, then the test is inconclusive.

Consider the given series $\sum_{n=1}^{\infty} n! \cdot 112n$ . In this case, $a_n =n! \cdot 112n$ , so , consider the limit

$\lim_{n\to\infty} \frac{(n+1)! 112 (n+1)}{n! 112 n} = \lim_{n\to\infty}\frac{(n+1)^2}{n}$

Since the numerator has a greater exponent than the numerator, the limit is infinity, which is greater than one, hence, the series diverge by the ratio test

7 0

3 years ago

I really need help with this and how you got it please 10 points!!

Kamila [148]

Answer:

1 and 7 are congruent

2 and 5 are supplementary

4 and 6 are congruent

3 and 8 are supplementary

8 0

3 years ago

Consider the following graph

Ksenya-84 [330]

Part C : is the answer

7 0

3 years ago