Answer :
Points at (1, 3) and (3, 3) and (2, 1)
Explanation:
The original graph (dashed) is an absolute value function meaning f(x) = |x|
<u>Given:</u> y = 2f(x - 2) + 1
f(x - 2) means you plug in x - 2 for x in f(x) function
the new graph equation is: y = 2|x - 2| + 1
- The graph will shift up 1 because +1
- The graph will shift right because -2
- The graph has a scale factor of 2
- The graph is V shaped because it is an absolute value graph
Learn more about Absolute Value here: brainly.com/question/729268
<u>Visual:</u>
What are you trying to do here?
Solve the graph, or make it appear as something else?
First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0
sec (x) (2sec (x) -2) = 0
Then we're going to separate the two to find the zeros of each because anything time 0 is zero.
sec(x) = 0
2sec (x) - 2 = 0
Now, let's simplify the second one as the first one is already.
Add 2 to both sides:
2sec (x) = 2
Divide by 3 on both sides:
sec (x) = 1
I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
1720 - 1040 = 680
680/7 = 97.1
I would put them in intervals of 100
Answer:the aser is d
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Step-by-step explanation:
