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3 years ago

7

Billy graphed the system of linear equations to find an approximate solution. y = x + y = x – 3 Which points are possible approx

imations for this system? Check all that apply. (1.9, 2.5) (2.2, –1.4) (2.2, –1.35) (1.9, 2,2) (1.9, 1.5)

2 answers:

valina [46]3 years ago

7 0

The correct answer is (2.2, -1.35) and (2.2, -1.4)

Your Welcome,

Could I be marked brainliest please?

Airida [17]3 years ago

7 0

Answer:

$(2.2,-1.4)$

$(2.2,-1.35)$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The solution of the system of linear equations is equal to the intersection point both graphs

In this problem

The x-coordinate of the intersection point belong to the interval

$(2,3)$

The y-coordinate of the intersection point belong to the interval

$(-2,-1)$

the points that are possible approximations for this system must be satisfy both intervals

Point $(1.9,2.5)$ -----> does not satisfy the interval of the x and y coordinates

Point $(2.2,-1.4)$ -----> is possible approximation for this system

Point $(2.2,-1.35)$ -----> is possible approximation for this system

Point $(1.9,2.2)$ -----> does not satisfy the interval of the x and y coordinates

Point $(1.9,1.5)$ -----> does not satisfy the interval of the x and y coordinates

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The number of students attending the fall play was 150 fewer then 3 times the number of adults. Together, students and adults pu

hodyreva [135]

Answer:

Number of students attended the fall play $=1296$

Step-by-step explanation:

Let number of adults $=x$

Number of students $=3\times number\ of\ adults-150=3x-150$

Given that total number of tickets $=1778$

Number of students+ Number of adults $=1778$

$x+(3x-150)=1778\\4x-150=1778\\4x=1778+150\\4x=1928\\x=\frac{1928}{4}\\x=482$

Number of adults $=482$

Number of students $=3x-150=3\times482-150=1446-150=1296$

Number of students $=1296$

4 0

3 years ago

Suppose the ages of multiple birth (3 or more babies) are normally distributed with a mean age of 31.7 years and a standard devi

artcher [175]

Answer:

The percent of these mothers are between the ages 30-35 is 36.53%

Step-by-step explanation:

we are given

mean of age =31.7 years

$\mu=31.7$

standard deviation of 5.2 years

$\sigma=5.2$

For age=30 years:

x=30

we can find z-score

$z=\frac{x-\mu}{\sigma}$

we can plug values

$z=\frac{30-31.7}{5.2}$

$z=-0.32692$

For age=35 years:

x=35

we can find z-score

$z=\frac{x-\mu}{\sigma}$

we can plug values

$z=\frac{35-31.7}{5.2}$

$z=0.63462$

now, we can use normal distribution table

$P(-0.32692$

now, we can find percentage

$=0.3653\times 100$

=36.53%

4 0

3 years ago

Distribute (b+10)(b+10)

ss7ja [257]

Answer:

b squared + 20b+ 100

Step-by-step explanation:

multiply Using the FOIL method

first inner outer last

so

b times b = b squared

10 times b equals 10b

b times 10 equals 10b (again)

10 times 10 equals 100

add up all the answers to get the final answer

b squared + 20b+ 100

7 0

3 years ago

What is the length of segment IO? (io) <br> G H I J K L M N O<br> -7-6-5-4-3-2-1 0 1

svet-max [94.6K]

The length of io equals -4

8 0

3 years ago

Alek and Ann start walking around a track at the same time and at the same place. It takes Ann 6 minutes to walk around the trac

Yuki888 [10]

Answer:

3 3/7 minutes

Step-by-step explanation:

This calculated using the formula:

1/x + 1/y = 1/n

Where

x = Number of minutes it took Ann to walk = 6 minutes

y = Number of minutes it took Alek to walk = 8 minutes

n = Number of minutes it would take An and Alek to reach the starting point at the same time

1/6 + 1/8 = 1/n

Lowest Common Denominator = 24

4 + 3/24 = 1/n

7/24 = 1/n

Cross Multiply

7n = 24

n = 24/7

n = 3 3/7 minutes

It would take them 3 3/7 minutes to reach the starting point at the same time.

3 0

2 years ago