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Virty [35]
3 years ago
9

What are the order of operations

Mathematics
2 answers:
Minchanka [31]3 years ago
8 0

Answer:

PEMDAS

Step-by-step explanation:

1) Parentheses

2) exponents

3) multiplication

4) division

5) addition

and finally 6) subtraction

Y_Kistochka [10]3 years ago
8 0
PEMDAS
Parentheses
Exponents
Multiplication or division (do left to right)
Addition or subtraction (left to right)

Or BIDMAS which is
Brackets
Indices
Division and multiplication
Addition and subtraction
Good luck!
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Commom denominator of 9 15
Rom4ik [11]

One common denominator is 45

6 0
3 years ago
−2x+5y=−17 3x-10y=283x−10y=28
AURORKA [14]

Answer:

x = 6

y = -1

Step-by-step explanation:

-2x + 5y = -17 ------ equation 1

3x- 10y = 28 ------- equation 2

equation 1× 2

-4x + 10y = -34 ------- equation 3

equation 2 + equation 3

-x = -6

x = 6

x = 6 substitute for equation 1

-12 + 5y = -17

5y = -5

y = -1

4 0
3 years ago
Given that M angle KLH equals 120° which statement about the figure must be true?
SVETLANKA909090 [29]

Answer:

m∠HLI = m∠ILM

Step-by-step explanation:

5 0
4 years ago
1. Over 3 years, how much more does $3000 in a savings account with an APR of 3.2% compounded
Sedbober [7]

Answer:

$1080

Step-by-step explanation:

((3000 \times 0.032) \times 2) \times 3 = 576

convert % to decimal by multiplying 3.2%x100=0.032

then multiply by initial amount 3000x0.032

then multiply by 2 because it's compounding semiannual

then multiply by 3 because it's over a 3 yr period

do the same for the quarterly compound but multiply by 4 because it's quarterly

((3000 \times 0.03) \times 2) \times3 = 1080

over a 3 yr period the quarterly compounded amount will earn:

1080 - 576 = 504

$504 more than the account compounded semiannual

5 0
3 years ago
Solve perfect square equation<br>х^2 +6х + 9 = 8​
LiRa [457]

Answer:

\large\boxed{x=-3-2\sqrt2\ \vee\ x=-2+2\sqrt2}

Step-by-step explanation:

x^2+6x+9=8\\\\x^2+2(x)(3)+3^2=8\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\(x+3)^2=8\iff x+3=\pm\sqrt8\\\\x+3=\pm\sqrt{4\cdot2}\\\\x+3=\pm\sqrt4\cdot\sqrt2\\\\x+3=\pm2\sqrt2\qquad\text{subtract 3 from both sides}\\\\x=-3-2\sqrt2\ \vee\ x=-2+2\sqrt2

8 0
4 years ago
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