Ask question

Ask question

All categories

2 years ago

11

In an 8 hour and 30 minute shift a patrolman drove 272 miles. What was his average rate(mph) during the shift?

2 answers:

scZoUnD [109]2 years ago

7 0

Answer:

32 mph

Step-by-step explanation:

To answer this, find the average rate of change

272 mi

------------- = 32 mph

8.5 hr

uysha [10]2 years ago

3 0

Answer:

32 mph

Step-by-step explanation:

We want to find the patrolman's rate in miles per hour during the shift. Since we want to find miles per hour, we must divide the miles he drove by the number of hours.

rate = miles / hours

He drove 272 miles.

rate = 272 miles / hours

He drove for 8 hours and 30 minutes. There are 60 minutes in 1 hour. One half of 60 is 30. Therefore, we can also say he drove eight and a half, or 8.5 hours.

rate= 272 miles / 8.5 hours

rate = 32 miles / hour

rate= 32 mph

His average rate during the shift was 32 miles per hour.

You might be interested in

If f(x) = 4x - 20, what is f(4)?<br> O A. -4<br> оо<br> O B. -12<br> O c. 4<br> O D. 16

4vir4ik [10]

Answer:

A. - 4

Step-by-step explanation:

f(4) = 4(4) - 20 = 16 - 20 = - 4

7 0

3 years ago

Read 2 more answers

I need an answer ASAP with an explanation please!

Butoxors [25]

Answer:

y intercept (0;4)

Step-by-step explanation:

let x = 0 because the graph will intersect the y-axis at the value of 0 for the x-axis

3 0

2 years ago

If x is a positive integer then the solution set of 4x+2<14 is

taurus [48]

4x + 2 < 14
4x < 14 - 2
4x < 12
x < 12/4
x < 3 S = { x <3 }

3 0

2 years ago

1. A system of linear equations that has one solution has slopes that are__________

algol13

Answer:

different

Step-by-step explanation:

different slopes gives one solution

same slopes with different constant has no solution

same slopes and constants has many solutions

3 0

2 years ago

Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of

fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Since, given the difference of the squares of the numbers is 5 that is $(x^2-y^2)^2=5$

And the product of the numbers is 6 that is $xy=6$

Using identity, we have,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Substitute, we have,

$(x^2+y^2)^2=(5)^2+(2(6))^2$

Simplify, we have,

$(x^2+y^2)^2=25+144$

$(x^2+y^2)^2=169$

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

5 0

2 years ago

Read 2 more answers