Simplify 1/4x-3/5-1/12 x+1/10

What is the area of the figure

BigorU [14]

Answer:

which one r u trying to do?

Step-by-step explanation:

6 0

3 years ago

Please help me on 1,2, and 3 please help

mart [117]

Answer: put it in rice<333

Step-by-step explanation:

5 0

3 years ago

(X^3+1)dividend (x-1)

bazaltina [42]

$x^3=x\cdot x^2$ and $x^2(x-1)=x^3-x^2$ . So we have a remainder of

$(x^3+1)-(x^3-x^2)=x^2+1$

$x^2=x\cdot x$ and $x(x-1)=x^2-x$ . Subtracting this from the previous remainder gives a new remainder

$(x^2+1)-(x^2-x)=x+1$

$x=x\cdot1$ and $1(x-1)=x-1$ . Subtracting this from the previous remainder gives a new one of

$(x+1)-(x-1)=2$

and we're done since 2 does not divide $x$ . So we have

$\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}$

4 0

3 years ago

Ragan makes beaded jewelry. The graph below shows the number of beads on varying cord lengths.

MakcuM [25]

Answer:

Option C) 34 inches

Step-by-step explanation:

We are given the following in the question:

The graph shows the number of beads on varying cord lengths.

The y-axis represents the number of beads and x-axis represents the cord length in inches.

The graph represents the equation:

$y = 2.52x + 1.61$

where y is the number of beads and x is the cord length.

We have to find the cord length of a necklace consisting of 88 beads.

Thus, we are given y = 88.

Putting this value in the equation, we get,

$y = 2.52x + 1.61\\88 = 2.52x + 1.61\\2.52x = 88 - 1.61\\2.52x = 86.39\\\\x = \displaystyle\frac{86.39}{2.52} = 34.28 \approx 34$

Thus, the cord length of necklace with 88 beads is approximatwly 34 inches.

8 0

3 years ago

Read 2 more answers

The statewide pass rates for ENGL&101 across Washington state community colleges is 68%. An instructor in the English depart

Mila [183]

Answer:

The calculated value Z=1.2413 < 1.96 at 0.05 level of significance

Null hypothesis is accepted

An instructor in the English department at CBC believes rates at CBC may be equal to the state average

Step-by-step explanation:

Step(i):-

Given Population proportion

P=68%= 0.68

Sample proportion

$p^{-} =\frac{x}{n} = \frac{179}{250} = 0.716$

Null hypothesis : H₀ : p = 0.68

Alternative Hypothesis :H₁ : p > 0.68

Step(ii):-

Test statistic

$Z = \frac{p^{-}-P }{\sqrt{\frac{P Q}{n} } }$

$Z = \frac{0.716-0.68 }{\sqrt{\frac{0.68 X 0.32}{250} } }$

Z = 1.2413

Level of significance

$Z_{0.05} = 1.96$

The calculated value Z=1.2413 < 1.96 at 0.05 level of significance

Null hypothesis is accepted

An instructor in the English department at CBC believes rates at CBC may be equal to the state average

6 0

4 years ago