Answer:
1/y -84
Step-by-step explanation:
7y/12-84
simplify= 1/y-84
Answer:
56.39 nm
Step-by-step explanation:
In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...
Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.
In order to have its longest constructive reflection at the red end (700 nm)

Here we take m=0.
Similarly for the constructive reflection at the blue end (400 nm)

Hence the thickness difference should be

Answer:
See Explanation
Step-by-step explanation:
The question is incomplete as the attachment of the prism is not given.
From the attachment:
-- Length
-- Width
-- Height
Required
Determine the volume
So, the volume is:



Answer:
Step-by-step explanation:
C=2πr
18=2×3.14×r
18=6.28r
r=2.88
Arc of a circle
A=®/360°πr
6=®/360°×3.14×r
®=239°
6
Answer:
72.1 and -48.1
Step-by-step explanation:
I set up the equations x + y = 24 and x*y=-3468. Then I substituted for y and used the quadratic formula to come to two numbers rounded to about 72.1 and -48.1. Hope that helps :)