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2 answers:
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Answer:
The average cost of each dinner at Dave's party is <u>$5.79</u>.
Step-by-step explanation:
Given:
Dave ordered dinner for a party of 10 people.
Three people ordered the $4.75 chicken dinner, two people ordered the $4.95 fish dinner, and five had the beef dinner at a cost of $6.75 each.
Now, to find the average cost of each dinner at Dave's party.
So, we get the total amount for the dinner:
Three people ordered the $4.75 chicken dinner.
Two people ordered the $4.95 fish dinner.
Five had the beef dinner at a cost of $6.75.
Total amount of dinner =
Now, to get the average cost of each dinner of 10 people we divide the total amount of dinner by 10:
Therefore, the average cost of each dinner at Dave's party is $5.79.