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Rainbow [258]
3 years ago
13

If csc Θ = 3/2 and the angle is in quadrant II, what is sec Θ?

Mathematics
1 answer:
harkovskaia [24]3 years ago
5 0

Answer:

sinθ = 1/cscθ = 2/3

cos²θ = 1 − sin²θ = 1−4/9 = 5/9

cosθ = −√5/3


secθ = 1/cosθ = −3/√5 = −3√5/5


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