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KonstantinChe [14]
2 years ago
7

A line intersects the points

Mathematics
1 answer:
Nimfa-mama [501]2 years ago
5 0
Y= -x+1 because the slope is negative
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The answer would be 9 feet.
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3 years ago
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A homogeneous rectangular lamina has constant area density ρ. Find the moment of inertia of the lamina about one corner
frozen [14]

Answer:

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner I_{corner} is:

I_{corner} = \int\limits \int\limits_R (x^2+y^2)  \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx

where :

(a and b are the length and the breath of the rectangle respectively )

I_{corner} =  \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx

I_{corner} =  \rho \int\limits^a_0 (bx^2 + \frac{b^3}{3})dx

I_{corner} =  \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}

I_{corner} =  \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Thus; the moment of inertia of the lamina about one corner is I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

7 0
3 years ago
A survey showed that 4 out of 5 students own a bicycle. Based on this result, how many of the 800 students in a school own a bic
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Answer:

640 students own a bicycle

Step-by-step explanation:

The rate shows that 4 out of 5 students own a bicycle. 4 out of 5 is 80% of the students. Now, we need to find 80% of 800 students.

To do this, we multiply the number of students by .80, which represents 80%.

800 x 0.8 = 640

I Hope That This Helps! :)

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3 years ago
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A store is having a sale where school supplies are 30% off their original price. A backpack is on sale for $11.20. What was the
Mrac [35]
To find the original price, you could use a variable to represent the original price in this equation;

Let p represent the original price

.70 × p=11.20

to solve this, we'd isolate the variable (p) 

p=11.20 ÷.70

p=16

The original price was $16
7 0
3 years ago
I need help on this thank you!
Digiron [165]
First off both triangles form a 90° angle there both congruent. you can tell they form a 90° angle because of square box
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