Note that (a^b)^c=a^(bc) so in this case we have:
(27^(1/3))^2 the cube root of 27=±3
(±3)^2 and ±3^2=9
So the equivalent expression is 9 or if you need an exponent 9^1 :)
I am assuming that you meant 27^(2/3)
State which of the following ordered pairs is a function. Set A: (-1, 0), (-2, 1), (4, 3), (3, 4) Set B: (1, 4), (2, 3), (3, 2),
liubo4ka [24]
Sets A and B are both functions because they all have different x values. Set C is not a function because it repeats the x value of 2 and gives it two different y values.
B) y = -2x
when x = a
y = -2a
when x= 2a
y = -2(2a) = -4a
