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2 years ago

2x + 8y=30 y=2 solve for x

Mathematics

2 answers:

FromTheMoon [43]2 years ago

7 0

Answer:

Step-by-step explanation:

2x+ 8(2)= 30

2x+ 16=30

2x=14

x=7

Licemer1 [7]2 years ago

3 0

The value for x is 23

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Question below pls hurry it’s timed

Gala2k [10]

Answer:

40ft perimeter

Step-by-step explanation:

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3 years ago

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What is the arithmetic of the following numbers? 4,9,6,3,4,2

Nezavi [6.7K]

Answer:

4.7

Step-by-step explanation:

Just do 28/6 and the simplify it to 14/3 and divide and get 4.6 repeating round it to 4.7

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2 years ago

An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo

Nata [24]

Answer:

482 km

63.94 degrees

Step-by-step explanation:

to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.

Cosine rule states that

C = $\sqrt{A^{2} + B^{2} -2AB cos(c) }$

where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060

solving now, we have

C = $\sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60) }$

C = $\sqrt{250000 + 90000 - [215000 cos(60) }]$

C = $\sqrt{340000 - [215000 * 0.5 }]$

C = $\sqrt{340000 - [107500 }]$

C = $\sqrt{232500}$

C = 482 km

The bearing can be gotten by using the Sine Rule.

$\frac{sina}{A}$ = $\frac{sinc}{C}$

sina/500 = sin60/482

482 sina = 500 sin60

sina = $\frac{500 sin60}{482}$

sina = 0.8983

a = sin^-1(0.8983)

a = 63.94 degrees

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2 years ago

Of equations to answer the questions.

iren [92.7K]

2x + 3(8 - 3x) = 3
2x + 24 -9x = 3
-7x = -21
x = 3

y = 8 - 3x
y = 8 - 3(3)
y = 8-9
y = -1

Check the math:
2(3) + 3(-1) = 6 - 3 = 3

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2 years ago

What are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotenuse is 15 units long?

Deffense [45]

So you have a right angle triangle. You need to use trig for this, as you have two values you can figure out a third.

You know that you have

90 deg. angle
19 deg. angle
Therefor you have 71 deg. angle

sin19 = x/15
15sin19 = x
x = 2.2

Now do Pythagoras c^2-b^2=a^2

a = 14.8

So the sides are 2.2 and 14.8 units long. (If these numbers are wrong tell me and I'll edit answer)

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2 years ago

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