Question

Write in slope-intercept form an equation of the line that passes through the given points.

Answer 1

Slope-intercept form uses the following equation: y = mx + b. m is the slope, and b is the y-intercept of the equation.

Use the following formula to figure out the rise and run of these points:

$\frac{y2 - y1}{x2 - x1}$

Plug the x and y values into the equation to determine the slope.

$\frac{5 - (-1)}{1 - (-1)}$ = $\frac{6}{2}$ = 3

Use the slope to find the y-intercept of the equation. You can find this by taking a point and using addition/subtraction and multiplication.

Taking the point (1,5), you can do the following:

5 - 3(1) = 2

The final equation is y = 3x + 2.

Answer 2

Answer: y=3x+2

Explanation:

Slope-intercept form: → $y=mx+b$

m: represents the slope and is constant.

b: represents the y-intercept.

The y-intercept is the point on a graph at which the graph crosses the y-axis.

Used rise/run.

$m=\frac{rise}{run}$

$rise=y^2-y^1$

$run=x^2-x^1$

$(x^1,y^1)=(-1,-1)$

$(x^2,y^2)=(1,5)$

$rise=y^2-y^1=5-(-1)$

$run=x^2-x^1=1-(-1)$

$\frac{5-(-1)}{1-(-1)}= \frac{6}{2}=3*2=6=3$

$5-3(1)=2(1)=2*1=2$

Hope this helps!

Thanks!