Answer:
a) 1 game
b) 41 goals
c) median = 2
Step-by-step explanation:
a)
As we can see in the line graph, where we have the 0 for the number of goals scored, the graph indicates only 1 in the number of games, so we have only 1 game where no goals were scored.
b)
To find the total number of goals scored, we multiply the goals scored by the number of games for that score, and then sum them all:
total goals = 1*0 + 4*1 + 5*2 + 6*3 + 1*4 + 1*5 = 41 goals
c)
To find the median, we put all the goals in crescent order, and then find the value in the middle. As we have 18 games, the middle value will be an average of the 9th and 10th terms.
We have 1 number 0, 4 numbers 1 and 5 numbers 2 in the beginning, so for these 10 numbers, the 9th and the 10th are the score 2, so the median is 2.
Answer:
(c) is m=1 i am working on the other ones
Answer:
5/4 P dollars
Step-by-step explanation:
Given that,
price of pony = P
Tax which is to added in the total price of pony = 25% of pony price
so, now total price of pony including its tax = P + 25%P
= P + 25/100 P
= P + 1/4 P
= 5/4 P dollars
= 1.25 P dollars
Answer:
y = 4 sin(½ x) − 3
Step-by-step explanation:
The function is either sine or cosine:
y = A sin(2π/T x) + C
y = A cos(2π/T x) + C
where A is the amplitude, T is the period, and C is the midline.
The midline is the average of the min and max:
C = (1 + -7) / 2
C = -3
The amplitude is half the difference between the min and max:
A = (1 − -7) / 2
A = 4
The maximum is at x = π, and the minimum is at x = 3π. The difference, 2π, is half the period. So T = 4π.
Plugging in, the options are:
y = 4 sin(½ x) − 3
y = 4 cos(½ x) − 3
Since the maximum is at x = π, this must be a sine wave.
y = 4 sin(½ x) − 3
Let's plug in the variables one by one.
6g - 2h
plug in 5 for g and 4 for h
6(5) - 2(4)
multiply
30 - 8
subtract
→ 22
20g
plug in 2 for g
20(2)
multiply
40
2(g + 1)
plug in 10 for g
2(10 + 1)
add
2(11)
multiply
→ 22
4g + 5h
plug in 1 for g and 4 for h
4(1) + 5(4)
multiply
4 + 20
add
24
Therefore, the answers that have a value of 22 are 6g - 2h and 2(g + 1)