1 is B
2 is A
3 is E
4 is C
5 is D
You use the equation Ax^2 + Bx + C to solve this equation.
The answer is 25.
I hope this helps :D
Given:
Anna’s cell phone plan charges her $30 per month plus a $150 one-time activation fee.
Evelyn’s cell phone plan charges her $20 per month, plus a $450 one-time activation fee.
To find:
The number of months after which the costs for the girls’ cell phone plans the same.
Solution:
Let x be the number of months.
Total cost = Fixed cost + Variable cost
According to the question, cost equation for Anna’s cell phone is
...(i)
Cost equation for Evelyn's cell phone is
...(ii)
Equate (i) and (ii) to find the time after which the costs for the girls’ cell phone plans the same.
![150+30x=450+20x](https://tex.z-dn.net/?f=150%2B30x%3D450%2B20x)
![30x-20x=450-150](https://tex.z-dn.net/?f=30x-20x%3D450-150)
![10x=300](https://tex.z-dn.net/?f=10x%3D300)
Divide both sides by 10.
![x=\dfrac{300}{10}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B300%7D%7B10%7D)
![x=30](https://tex.z-dn.net/?f=x%3D30)
Therefore, the costs for the girls’ cell phone plans the same after 10 months.
Answer:
X
Step-by-step explanation:
X
This question is an example of what we call "system of equations". We can use two separate equations to help us solve.
Let a = number of touchdowns
Let b = number of field goals
a + b = 43
7a + 3b = 301
We can solve this system using the elimination method.
1. a + b - b = 43 + -b (add - b to both sides)
a = -b + 43
2. substitute -b + 43 for a in 7a + 3b = 301
7 (-b +43) + 3b = 301
-4b + 301 = 301 (simplify both sides of the equation)
-4b + 301 - 301 = 301 - 301 (add -301 to both sides)
-4b = 0
b = 0
Since b = 0, and b is the number of field goals, we know that Liam's team did not score any field goals. Which means the only points from his team came from touchdowns. So, 43 touchdowns were scored, and 0 field goals were scored, for a total of 301 points.