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svp [43]
3 years ago
12

What is the solution to the inequality? X-7>-6

Mathematics
1 answer:
Likurg_2 [28]3 years ago
4 0
The equation is saying x minus 7 is greater than -6, so treat the inequality symbol just how you would with a normal =. So x-7=-6, you need to find x, so to find x you need to keep x alone. So you get rid of the -7, so to do that since it is a negative you add 7 to -6, so that would mean that x=1. Now you put the inequality symbol back. So now it's x>1. This is the solution, x is greater than 1, or x>1. Hope this helps
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LekaFEV [45]

Answer:

\bullet\quad\overline{QR}\cong\overline{ST}\text{ and }\overline{QR}\parallel\overline{ST}\\\\\bullet\quad\overline{QR}\cong\overline{ST}\text{ and }\overline{QT}\cong\overline{RS}

Step-by-step explanation:

A quadrilateral is a parallelogram when opposite sides are parallel. This will be the case when ...

  • one pair of opposite sides are parallel and the same length (choice B)
  • each pair of opposite sides is the same length (choice E)

An isosceles trapezoid has one pair of parallel sides and the other pair of opposite sides the same length, so that is not sufficient to describe a parallelogram. (Choices A and C describe this condition.)

A line segment is always congruent to itself, so that fact establishes nothing about a parallelogram. (choice D)

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<em>Comment on opposite sides equal</em>

Choice E can also describe an hourglass-shaped figure. We assume here that the quadrilateral is convex, with no sides crossing each other.

4 0
3 years ago
Pls help me kind sir or madam
NemiM [27]

Answer:

7 {t}^{2}  + 21t

Step-by-step explanation:

There are total 7 rectangles of same dimensions.

\therefore \: Area  \:  of  \: pattern  \\ = 7 \times  Area  \:  of  \: one \:  rectangle  \\  = 7t(t + 3) \\  = 7 ({t}^{2}  +  3t) \\  = 7 {t}^{2}  + 21t \\  \\  \red{ \bold{Area  \:  of  \: pattern = 7 {t}^{2}  + 21t }}\\

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How many distinct triangles can be drawn using three of the dots below as vertices?
Dima020 [189]

Answer:

18

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₆C₃ = 6! / (3! (6−3)!)

₆C₃ = 6! / (3! 3!)

₆C₃ = 6×5×4 / (3×2×1)

₆C₃ = 20

However, 2 of these combinations are lines, not triangles.

So there are 18 possible distinct triangles.

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18 - 2,3,6,8
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Wewaii [24]

Since irrational numbers go on forever, no matter how much you add or multiply rational numbers, irrational numbers remain irrational.

5 0
4 years ago
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