What has more inertia? Hammer or Feather?

g For each of the following cases, indicate whether the first entity is greater than, less than or equal to the second entity. W

Marianna [84]

Answer:

Explanation

check the solution in the attached

7 0

3 years ago

Experiments with rats show that if rats are dosed with 3.0 mg/kg of cocaine (that is, 3.0 mg cocaine per kg of animal mass), the

Aliun [14]

Answer:

The molecules of dopamine would be produced in a rat after 60 seconds of a 3.0 mg/kg dose of cocaine is $2.258\times 10^{12} molecules$ .

Explanation:

Concentration of dopamine = 0.75 μM = $7.5\times 10^{-7} M$

1 μM = $10^{-6} M$

Volume of the brain in which dopamine is produced = $V=5.00 mm^3$

$1 mm^3=10^{-6} L$

$V = 5.00\times 10^{-6} L$

Moles of dopamine = n

$Concentration=\frac{moles}{Volume}$

$7.5\times 10^{-7} M=\frac{n}{5.00\times 10^{-6} L}$

$n=7.5\times 10^{-7} M\times 5.00\times 10^{-6} L=3.75\times 10^{-12} mol$

$1 mol = 6.022\times 10^{23} molecules$

So, molecules in $3.75\times 10^{-12} mol$ of dopamine :

$3.75\times 10^{-12}\times 6.022\times 10^{23}=2.258\times 10^{12} molecules$

4 0

3 years ago

In the gaseous state, chlorine exists as a diatomic molecule Cl2 (Molar mass = 70.9 g/mol). Calculate the number of moles of chl

kap26 [50]

Cl is stable as a diatomic molecule where the 2 Cl atoms are held together by a covalent bond

molar mass of the diatomic molecule is 70.9 g/mol

therefore 70.9 g of Cl₂ is - 1 mol

then 140 g of Cl₂ is - 1/70.9 x 140 = 1.97 mol

there are 1.97 mol of Cl₂ present

8 0

3 years ago

Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of water is pro

Lubov Fominskaja [6]

This is an incomplete question, here is a complete question.

Aqueous sulfuric acid (H₂SO₄) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium sulfate (Na₂SO₄) and liquid water (H₂O) . If 12.5 g of water is produced from the reaction of 72.6 g of sulfuric acid and 77.0 g of sodium hydroxide, calculate the percent yield of water. Round your answer in significant figures.

Answer: The percent yield of water is, 46.8 %

Explanation : Given,

Mass of $H_2SO_4$ = 72.6 g

Mass of $NaOH$ = 77.0 g

Molar mass of $H_2SO_4$ = 98 g/mol

Molar mass of $NaOH$ = 40 g/mol

First we have to calculate the moles of $H_2SO_4$ and $NaOH$ .

$\text{Moles of }H_2SO_4=\frac{\text{Given mass }H_2SO_4}{\text{Molar mass }H_2SO_4}$

$\text{Moles of }H_2SO_4=\frac{72.6g}{98g/mol}=0.741mol$

and,

$\text{Moles of }NaOH=\frac{\text{Given mass }NaOH}{\text{Molar mass }NaOH}$

$\text{Moles of }NaOH=\frac{77.0g}{40g/mol}=1.925mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

From the balanced reaction we conclude that

As, 1 mole of $H_2SO_4$ react with 2 mole of $NaOH$

So, 0.741 moles of $H_2SO_4$ react with $0.741\times 2=1.482$ moles of $NaOH$

From this we conclude that, $NaOH$ is an excess reagent because the given moles are greater than the required moles and $H_2SO_4$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $H_2O$