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pashok25 [27]
2 years ago
8

Are all flourides soluble?

Chemistry
1 answer:
Katen [24]2 years ago
6 0

Answer:

Solution : The common fluorides `(F^(-))` are soluble in water except `MgF_(2), CaF_(2), SrF_(2), BaF_(2), PbF_(2)`. <br> Beryllium fluoride (a predominantly convent compound) is very soluble in water, owing to the high solvation energy of Be in forming `[Be(H_(2)O)_(4)]^(2+)

Explanation:

Hope it's helpful to you

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. What is the mass, in grams, of a sample of 7.83 × 1024 atoms of helium (He)?
erica [24]
Moles He = 7.83 x 10^24 / 6.02 x 10^23 =13.0 

<span>mass He = 13.0 mol x 4.00 g/mol = 52.0 g</span>
6 0
3 years ago
Select the properly written and balanced equation for the following chemical reaction: Sodium metal and an aqueous solution of m
Setler [38]

Answer:2Na(s)+MgI_2 (aq)\rightarrow 2NaI(aq)+Mg(s)

Explanation: The chemical reaction is written by writing down the chemical formulas of the reactants on the left hand side and the chemical formulas of products on the right hand side separated by a right arrow.

This is a single displacement reaction in which a more reactive element displaces the less reactive element from its salt solution. Thus sodium is more reactive than Mg and thus displaces it from MgI_2.

2Na(s)+MgI_2 (aq)\rightarrow 2NaI(aq)+Mg(s)

The number of atoms of each element must be same on both sides of the reaction so as to follow the law of conservation of mass. Thus the equation is balanced.

5 0
3 years ago
you produce 115 grams of water in a combustion reaction. how much methane do you need in grams for this to react?
lora16 [44]

Answer:about 2 grams of methane

Explanation:

idk just got this right

6 0
3 years ago
Nickel + oxygen = nickel oxide. What is the balanced redox reaction?
uranmaximum [27]

Answer:

This is an oxidation-reduction (redox) reaction:

2 Ni0 - 4 e- → 2 NiII

(oxidation)

2 O0 + 4 e- → 2 O-II

(reduction)

Ni is a reducing agent, O2 is an oxidizing agent.

7 0
3 years ago
The reaction below will occur in a gaseous system at STP:
WARRIOR [948]

Answer:

V = 12.5 L

Explanation:

Given data:

Volume of NO = 15.0 L

Temperature and pressure = standard

Volume of nitrogen gas produced = ?

Solution:

Chemical equation:

6NO + 4NH₃    →     5N₂ + 6 H₂O

Number of moles of NO:

PV = nRT

n = PV/RT

n = 1 atm × 15.0 L / 0.0821 atm.L /mol.K × 273.15 K

n = 15.0 atm.L / 22.43 atm.L /mol

n = 0.67 mol

now we will compare the moles of No and nitrogen gas.

              NO           :         N₂

               6             :          5

              0.67         :         5/6×0.67 = 0.56

Volume of nitrogen gas:

 PV = nRT

1 atm × V = 0.56 mol ×  0.0821 atm.L /mol.K × 273.15 K

V = 12.5 atm.L / 1 atm

V = 12.5 L

4 0
3 years ago
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