Answer:
15.0 mL
Explanation:
Please see the step-by-step solution in the picture attached below.
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Answer:
Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals.
Fractional distillation is used for the refining of crude petroleum.
<h3>How are the components of
crude petroleum separated out?</h3>
Fractional distillation is the procedure used to separate crude oil's numerous constituents.
- A mixture is divided into several components, known as fractions, using fractional distillation.
- A combination of hydrocarbons makes up crude oil. The crude oil evaporates, and in the fractionating column, its vapors condense at various temperatures.
- The hydrocarbon molecules in each percent have a comparable number of carbon atoms and a comparable range of boiling points.
- The mixture is placed above a tall fractionating column that has multiple condensers coming off at various heights.
- The bottom of the column is warm, while the top is cool. High boiling point compounds condense at the bottom, whereas low boiling point substances condense as they ascend.
Learn more about fractional distillation here:
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Answer:
computer model
Explanation:
Computer models are cheaper to set up than alternative methods that could be used to predict what will happen in a system, ex. building a prototype. Other benefits include being able to: make alterations and quickly see the outcomes.
Answer:
Explanation:
The formula of the reaction:
KClO₂ → KCl + O₂
To assign oxidation numbers, we have to obey some rules:
- Elements in an uncombined state or one whose atoms combine with one another to form molecules have an oxidation number of zero.
- The charge on simple ions signifies their oxidation number.
- The algebraic sum of all the oxidation number of all atoms in a neutral compound is zero. For radicals with charges, their oxidation number is the charge.
The oxidation number of K in KClO₂:
K + (-1) + 2(-2) = 0
K-5 = 0
K = +5
The oxidation number of K in KCl:
K + (-1) = 0
K = +1
The oxidation number Cl in KClO₂ is -1
For Cl in KCl, the oxidation number is -1
For O in KClO₂, the oxidation number is (2 x -2) = -4
For O in O₂, the oxidation number is 0
K moves from an oxidation state of +5 to +1. This is a gain of electrons and K has undergone reduction. We then say K is reduced.
O moves from an oxidation state of -4 to 0. This is a loss of electrons and O has undergone oxidation. We say O is oxidized.
