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3 years ago

What is the first step in writing f(x) = 6x2 + 5 – 42x in vertex form?

1 answer:

7 0

The first step to getting this in vertex form would be to put this in proper standard form. This is so that you can split the middle term which is a step of completing the square.

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Sus crib ete a mi canal de You tube me llamo <br><br>Leeom 47<br><br>porfa

Alex Ar [27]

Answer:

Ightt

Step-by-step explanation:

7 0

3 years ago

Woodland Bicycles makes two models of off-road bicycles: the Explorer, which sells for $250, and the Grande Expedition, which se

elena-s [515]

Answer:

Step-by-step explanation:

Let X be number of woodland bicyles and Y grande expedition

Our objective is to maximize profit

Z = 250x+350Y

Constraints are: 2x+3y<450 and

x+y<375

(given)

Solution gives negative y. Hence intersecting point is not within constraint.

So choices satisfying the constraints would be min of 225, 375 for x and min of 150,375 for x

i.e x=225 and y =150

To maximize revenue 225 Woodland and 150 Grande to be produced

4 0

3 years ago

Read 2 more answers

(07.04)

dolphi86 [110]

Answer:

1. 6

2. $1.63

3. 4.6

4. 32

5. 34n = 306

6. 3/8

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Which of the following values are in the domain of the function graphed

Mice21 [21]

Answer:

A. -2
B. -1
D. 0
E. 4

Step-by-step explanation:

The domain includes all x values, and here, it is [-2, 4].

6 0

2 years ago

I get

dybincka [34]

Answer:

Absolute minimum = 1.414

Absolute maximum = 2.828

Step-by-step explanation:

$g(x,y)=\sqrt {x^2+y^2} \ constraints: 1\leq x\leq 2 ,\ 1\leq y\leq2$

For absolute minimum we take the minimum values of $x$ and $y$ .

$x_{minimum} =1\\y_{minimum}=1\\$

Plugging in the minimum values in the function.

$g(1,1)=\sqrt {1^2+1^2}\\g(1,1) = \sqrt{1+1}\\g(1,1)=\sqrt {2}\\g(1,1)=\pm 1.414\\$

Absolute minimum value will be always positive.

∴ Absolute minimum = 1.414

For absolute maximum we take the maximum values of $x$ and $y$ .

$x_{maximum} =2\\y_{maximum}=2\\$

Plugging in the maximum values in the function.

$g(2,2)=\sqrt {2^2+2^2}\\g(2,2) = \sqrt{4+4}\\g(2,2)=\sqrt {8}\\g(2,2)=\pm 2.828\\$

Absolute maximum value will be always positive.

∴ Absolute maximum = 2.828

3 0

3 years ago