Answer:
![a_n=-7+4(n-1)](https://tex.z-dn.net/?f=a_n%3D-7%2B4%28n-1%29)
or
![a_n=-7+(n-1)(4)](https://tex.z-dn.net/?f=a_n%3D-7%2B%28n-1%29%284%29)
Step-by-step explanation:
-7,-3,1,5,... is a arithmetic sequence.
Arithmetic sequences have a common difference. That is, it is going up by 4 each time.
When you see arithmetic sequence, you should think linear equation.
The point-slope form of a line is
.
m is the common difference, the slope.
Any they are using the point at x=1 in the point slope form. So they are using (1,-7).
So let's put this into our point-slope form:
![y-(-7)=4(x-1)](https://tex.z-dn.net/?f=y-%28-7%29%3D4%28x-1%29)
![y+7=4(x-1)](https://tex.z-dn.net/?f=y%2B7%3D4%28x-1%29)
Subtract 7 on both sides:
![y=-7+4(x-1)](https://tex.z-dn.net/?f=y%3D-7%2B4%28x-1%29)
So your answer is
![a_n=-7+4(n-1)](https://tex.z-dn.net/?f=a_n%3D-7%2B4%28n-1%29)
We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:
![\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%201-%5Calpha%3D0.98%20%5C%5C%20%5Calpha%3D0.02%20%5Cend%7Bgathered%7D)
The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:
![CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack](https://tex.z-dn.net/?f=CI%28%5Cmu%29%3D%5Clbrack%20x-Z_%7B1-%5Cfrac%7B%5Calpha%7D%7B2%7D%7D%5Ccdot%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D%2Cx%2BZ_%7B1-%5Cfrac%7B%5Calpha%7D%7B2%7D%7D%5Ccdot%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D%5Crbrack)
Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:
![CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack](https://tex.z-dn.net/?f=CI%28%5Cmu%29%3D%5Clbrack30.0-Z_%7B0.99%7D%5Ccdot%5Cfrac%7B2.40%7D%7B%5Csqrt%5B%5D%7B28%7D%7D%2C30.0%2BZ_%7B0.99%7D%5Ccdot%5Cfrac%7B2.40%7D%7B%5Csqrt%5B%5D%7B28%7D%7D%5Crbrack)
Where (from tables):
![Z_{0.99}=2.33](https://tex.z-dn.net/?f=Z_%7B0.99%7D%3D2.33)
Finally, the interval at 98% confidence level is:
The 3 panes would cost $7.65.
(-4,4) (3,-2)
formula for finding mid point is
M=(x1+x2/2,y1+y2/2)
m=-4+3/2,4-2/2
m=(-1/2,1)
If we have 420 books for every 7 shelves and are looking for how many books are on 4 shelves, we need to set up fractional proportions.
We have 7 shelves for every 420 books, so we will have our first fraction like this:
7/420.
We also have 4 shelves for every x books, so our second fraction will be 4/x.
Set these fractions up as an equation.
7/420 = 4/x
To solve for x, we need to cross multiply the numerators of one fraction with the denominators of the other fraction.
In other words, multiply the top number of one fraction by the bottom number of the other question.
It should look like this:
7(x)
420(4)
7(x) = 7x
420(4) = 1680
Set your products up as an equation.
7x = 1680
Now to solve for x, we need to simplify.
Currently, x is being multiplied by 7.
To get x alone, divide 7x by 7.
Remember, what you do to one side of an equation, you must do to the other, so divide 1680 by 7.
7x / 7 = x
1680 / 7 = 240
You are left with:
x = 240.
For every 4 shelves you have 240 books.
I hope this helps!