Answer:
.
Explanation:
Based on the electron configuration of this ion, count the number of electrons in this ion in total:
.
Each electron has a charge of
.
Atoms are neutral and have
charge. However, when an atom gains one extra electron, it becomes an ion with a charge of
. Likewise, when that ion gains another electron, the charge on this ion would become
.
The ion in this question has a charge of
. In other words, this ion is formed after its corresponding atom gains two extra electrons. This ion has
electrons in total. Therefore, the atom would have initially contained
electrons. The atomic number of this atom would be
.
Refer to a modern copy of the periodic table. The element with an atomic number of
is sulphur with atomic symbol
. To denote the ion, place the charge written backwards ("
" for a charge of
) as the superscript of the atomic symbol:
.
Answer:
Option D is Correct answer
Answer:
Helium
Explanation:
The first ionization energy varies in a predictable way across the periodic table.
Answer:
- 278.85 J
Explanation:
Given that:
Pressure = 1.1 atm
The initial volume V₁ = 0.0 L
The final volume V₂ = 2.5 L
The work that takes place in a reaction at constant pressure can be expressed by using the equation:
W = P(V₂ - V₁ )
Since the volume of the gas is expanded from 0 to 2.5 L when 1.1 atm pressure is applied. Then, the work can be given by the expression:
W = - P(V₂ - V₁ )
W = -1.1 atm ( 2.5 - 0.0) L
W = -1.1 atm (2.5 L)
W = -2.75 atm L
Recall that:
1 atm L = 101.4 J
Therefore;
-2.75 atm L = ( -2.75 × 101.4 )J
= -278.85 J
Thus, the work required at the chemical reaction when the pressure applied is 1.1 atm = - 278.85 J