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3 years ago

A screw has 4 threads per centimeter and a circumference of 2 centimeters. The mechanical advantage of the screw is?

Chemistry

2 answers:

Anna71 [15]3 years ago

8 0

Answer:

Mechanical advantage = 8

Explanation:

It is given that,

A screw has 4 threads per centimeter.

The circumference of the screw, C = 2 cm = 0.02 m

The mechanical advantage of a screw is given by :

$MA=\dfrac{circumference}{pitch}$ .............(1)

Pitch of a screw is defined as the number of threads per inch on the screw i.e.

Pitch = 1 / number of threads per inch or cm

or pitch = 1/4

$MA=\dfrac{2}{1/4}$

MA = 8

Hence, the mechanical advantage of the screw is 8.

sashaice [31]3 years ago

3 0

<span>The answer is 8. Hope this help!!!

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g In the elimination reaction of t-butanol and t-butyl bromide. A. They have a common intermediate and require a strong base B.

11111nata11111 [884]

Answer:

Both reactions share a common intermediate and differ only in the leaving group

Explanation:

The elimination reaction of tertiary alkyl halides usually occur by E1 mechanism. In E1 mechanism, the substrate undergoes ionization leading to the loss of a leaving group and formation of a carbocation.

Loss of a proton from the carbocation completes the reaction mechanism yielding the desired alkene.

In the cases of t-butanol and t-butyl bromide, the mechanism is the same. The both reactions proceed by E1 mechanism. The leaving groups in each case are water and chloride ion respectively.

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2 years ago

You are trying to determine the specific heat of a metal. You heat the 97 g piece of metal to 100 °C and place it in a calorimet

Brut [27]

Answer : The specific heat of the metal is, $0.658J/g^oC$

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of metal = ?

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of metal = 97 g

$m_2$ = mass of water = 122 g

$T_f$ = final temperature of mixture = $28.9^oC$

$T_1$ = initial temperature of metal = $100^oC$

$T_2$ = initial temperature of water = $20.0^oC$

Now put all the given values in the above formula, we get

$97g\times c_1\times (28.9-100)^oC=-122g\times 4.18J/g^oC\times (28.9-20.0)^oC$

$c_1=0.658J/g^oC$

Therefore, the specific heat of the metal is, $0.658J/g^oC$

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3 years ago

Describe in detail what you know about the enthalpy, entropy, and free energy changes when a sample of gas condenses to a liquid

ycow [4]

The keyword here is gas condenses to a liquid, which mean we're talking about condensation process

The enthalpy energy in condensation process is negative because it releases energy
The entropy in general will also decreases .

Temperature affect this change because it will create free energy if added with this result

hope this helps

8 0

3 years ago

Read 2 more answers

A histidine is involved in an interaction with a glutamic acid that stabilizes the charged form of the histidine, such that the

Greeley [361]

Answer:

pKa of the histidine = 9.67

Explanation:

The relation between standard Gibbs energy and equilibrium constant is shown below as:

$\Delta{G^0} =-RT \ln \frac{[His]}{[His+]}$