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3 years ago

Main group elemants are arranged in _______ groups

Chemistry

1 answer:

Lorico [155]3 years ago

3 0

Answer: susuus

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Explanation: sjsjsj

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The equilibrium constant for the reaction Ni2+(aq) + 6 NH3(aq) ⇌ Ni(NH3)6 2+(aq) is Kf = 5.6 × 108 at 25°C. (a) What is ΔG o at

shusha [124]

Answer:

(a) -49.9 kJ/mol;

(b) To the right;

(c) 34.6 kJ/mol

Explanation:

(a) For this reaction, since it's at equilibrium and standard states, we know that we can apply the equation:

$\Delta G^o = -RT ln (K_f)$

Substituting the given variables:

$\Delta G^o = -8.314 \frac{J}{K mol}\cdot 298.15 K\cdot ln (5.6\cdot 10^8) = -49932 J/mol = -49.9 kJ/mol$

(b) Notice that this reaction is spontaneous, since $\Delta G^o < 0$ . This means reaction spontaneously proceeds to the right side. Besides, K > 1, this means products dominate over reactants, so reaction proceeds to the right.

(c) Given the expression of the formation constant, we can use the same expression to calculate the reaction quotient at non-standard conditions:

$Q_f = \frac{[Ni(NH_3)_6]^{2+}}{[Ni^{2+}][NH_3]^6} = \frac{0.010}{0.0010\cdot 0.0050^6} = 6.4\cdot 10^{14}$

Now, notice that $Q_f > K_f$ . In this case, we have an excess of the products, this means reaction will shift to the let left to restore the equilibrium.

Calculate:

$\Delta G = \Delta G^o + RT ln Q_f = -49932 J/mol + 8.314 \frac{J}{K mol}\cdot 298.15 K\cdot ln(6.4\cdot 10^{14}) = 34577 J = 34.6 kJ/mol$

5 0

3 years ago

Need help!!!

Greeley [361]

Explanation:

here u go kid , welcome kid :)

5 0

3 years ago

At a fixed pressure, if the temperature is doubled, the volume of a gas will be

Scrat [10]

Answer:

Doubled.

Explanation:

The relationship between the temperature and the volume of a gas at a constant pressure can be described using Charles' law:

V₁*T₂ = V₂*T₁

That means that the temperature and the volume of a gas are directly proportional: The higher the temperature, the higher the pressure. If one of those factors is increased twofold, the other one will be increased twofold as well.

7 0

3 years ago

Draw the products of the acid-base reaction between stearic acid and OH-

jok3333 [9.3K]

Answer:

Products are stearate anion and water.

Explanation:

Stearic acid is a 18-carbon chain molecule containing -COOH group. IUPAC name of stearic acid is octadecanoic acid.

Molecular formula of stearic acid is $C_{17}H_{35}CO_{2}H$ .

When $OH^{-}$ is added into stearic acid, $OH^{-}$ removes a proton ( $H^{+}$ ) from acidic -COOH group and forms stearate anion and water as products.