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gayaneshka [121]
3 years ago
15

Which of these is not a possible r-value?

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
7 0

Answer:

a. 1.75

Step-by-step explanation:

r values, or the correlation coefficient  must be between -1 and 1, inclusive

-1 is a perfect negative correlation

0 is no correlation

+1 is a perfect positive correlation

1.75 is not between -1 and 1

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What is the value of |−32|?
kolezko [41]

Answer:

32

Step-by-step explanation:

|-32|

Absolute values means take the positive value of

|-32| = 32

7 0
2 years ago
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Anna and kim shared 49 jellybeans in the ratio 3:4.Howw many jellybeans did kim receive​
lina2011 [118]
Solution - 49 jellybeans divided by 7 for the ration purposes = 7 so 1/7 the ratio is 7
Therefore Kim having 4/7 is 4 X 7

Answer - 28
4 0
3 years ago
As his empire spread throughout the ancient world, Alexander founded roughly how many cities?
Studentka2010 [4]
About 70 Cities in Total.

For his more noteworthy grandness, Alexander established exactly 70 urban areas in the grounds he vanquished and requested them named after himself. Most celebrated, obviously, is Alexandria in Egypt. In India, when his dearest horse kicked the bucket, he requested a city to be constructed named Bucephala.
6 0
3 years ago
Please answer, the best answer gets brainliest
puteri [66]

Answer:

Median is 18.

Mean is 22.

Step-by-step explanation:

Median has to be ordered from least to greatest:

1, 9, 17, 18, 25, 41, 43

then the median is the number in the middle, which is 18.

Mean is the sum of all the numbers, divided by 7 (because there are 7 numbers given)

25+18+9+1+43+17+41= 154

154/7 = 22

8 0
2 years ago
Read 2 more answers
What is the solution set of x2 + y2 = 26 and x − y = 6? A. {(5, -1), (-5, 1)} B. {(1, 5), (5, 1)} C. {(-1, 5), (1, -5)} D. {(5,
Rus_ich [418]
He two equations given are
x^2 + y^2 = 26
And
x - y = 6
x = y +6
Putting the value of x from the second equation to the first equation, we get
x^2 + y^2 = 26
(y + 6) ^2 + y^2 = 26
y^2 + 12y + 36 + y^2 = 26
2y^2 + 12y + 36 - 26 = 0
2y^2 + 12y + 10 = 0
y^2 + 6y + 5 = 0
y^2 + y + 5y + 5 = 0
y(y + 1) + 5 ( y + 1) = 0
(y + 1)(y + 5) = 0
Then 
y + 1 = 0
y = -1
so x - y = 6
     x + 1 = 6
x = 5
Or
y + 5 = 0
y = - 5
Again x = 1
So the solutions would be (-1, 5), (1 , -5). The correct option is option "C".

4 0
3 years ago
Read 2 more answers
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