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aniked [119]
3 years ago
15

The weight of an African elephant is 6x10^6 grams; the weight of a tiger is 3x10^5 grams. How many times heavier is the elephant

than the tiger?
Mathematics
2 answers:
Stolb23 [73]3 years ago
7 0
The answer would be 20 times longer.
Marina CMI [18]3 years ago
5 0
So that means
elephant= x times tiger

6 times 10^6=x times 3 times 10^5
divide both sides by (3 times 10^5)
remember that (x^m)/(x^n)=x^(m-n)
so
(6 times 10^6)/(3 times 10^5)=x
(6/3) times (10^6)/(10^5)=x
2 times 10^1=x
2 times 10=x

that would be 2 times 10^1 or 20 times
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Answer:

The height of right circular cone is h = 15.416 cm

Step-by-step explanation:

The formula used to calculate lateral surface area of right circular cone is: s=\pi r\sqrt{r^2+h^2}

where r is radius and h is height.

We are given:

Lateral surface area s = 236.64 cm²

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Putting values in the formula and finding height:

s=\pi r\sqrt{r^2+h^2}\\236.64=3.14(4.75)\sqrt{(3.75)^2+h^2} \\236.64=14.915\sqrt{(3.75)^2+h^2} \\\frac{236.64}{14.915}=\sqrt{14.0625+h^2}  \\15.866=\sqrt{14.0625+h^2} \\Switching\:sides\:\\\sqrt{14.0625+h^2} =15.866\\Taking\:square\:on\:both\:sides\\(\sqrt{14.0625+h^2})^2 =(15.866)^2\\14.0625+h^2=251.729\\h^2=251.729-14.0625\\h^2=237.6665\\Taking\:square\:root\:on\:both\:sides\\\sqrt{h^2}=\sqrt{237.6665} \\h=15.416

So, the height of right circular cone is h = 15.416 cm

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