You forgot to include the given line.
We need the given line to find the slope. The slope of parallel lines are equal. So, the slope of the line of the equation you are looking for is the same slope of the given line.
I can explain you the procedure to help you to find the desired equation:
1) Slope
Remember that the slope-intercept equation form is y = mx + b where m is the slope and b is thye y-intercept.
If you clear y in every equation you get:
a) y = (3/4)x + 17/4 => slope = 3/4
b) y = (3/4)x + 20/4 = (3/4)x + 5 => slope = 3/4
c) y = -(4/3)x - 2/3 => slope = -4/3
d) y = (-4/3)x - 6/3 = (-4/3)x - 2 => slope = -4/3
So, you just have to compare the slope of the given line with the above slopes to see which equations are candidates.
2) Point (-3,2)
You must verify which equations pass through the point (-3,2).
a) 3x - 4y = - 17
3(-3) - 4(2) = -17
- 9 - 8 = - 17
- 17 = - 17 => it is candidate
b) 3x - 4y = - 20
- 17 ≠ - 20 => it is not candidate
c) 4x + 3y = - 2
4(-3) + 3(2) = - 2
-12 + 6 = - 2
-6 ≠ -2 => it is not candidate
d) 4x + 3y = - 6
-6 = - 6 => it is candidate
3) So, the point (-3,2) permits to select two candidates
3x - 4y = - 17, and 4x + 3y = -6.
4) Yet you have to find the slope of the given equation, if it is 3/4 the solutions is the equation 3x - 4y = -17; if it is -4/3 the solution is the equation 4x + 3y = -6.
Joe runs one lap around a track in 80 seconds. Joe and Jim meet after 30 seconds.We know how long does it take for Joe to run one lap, so we can calculate what distance he runs in 30 seconds:
He runs half lap for 40 seconds. He runs quarter lap for 20 minutes and he runs 1/8 lap for ten minutes. So for 30 seconds he runs 3 * 1/8 lap=3/8 lap.
Because Jim runs in opposite direction this means that he will meat with Joe at 1-3/8=5/8 lap. So, Jim runs 5/8 lap for 30 seconds.
1/8 lap Jim runs for 30/5=6 seconds, so Jim needs 8*6=48 seconds to run the lap.
After 30 seconds Joe has run e runs
Considering the graph of the velocity of the car, it is found that the interval in which it was stopped at a traffic light was:
Between 3 and 4 minutes.
<h3>When is a car stopped at a traffic light?</h3>
When a car is stopped at a traffic light, the car is not moving, that is, it's velocity is of zero.
In this problem, the graph gives the <u>velocity as a function of time</u>, and it is at zero between 3 and 4 minutes, hence the interval in which it was stopped at a traffic light was:
Between 3 and 4 minutes.
More can be learned about the interpretation of the graph of a function at brainly.com/question/3939432
#SPJ1
Answer:
Option B, At least three will have the transponder
Step-by-step explanation:
<u>Step 1: Find the probability in 6 cars</u>
6 * %80 or 6 * 0.8
4.8
Answer: Option B, At least three will have the transponder
