XY=7a,YZ=5a,XZ=6a+24
1 answer:
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Given:
The given point is (4,12).
To find:
The equation that would NOT contain the point (4,12).
Solution:
We need to check each equation for the point (4,12).
In option A, the given equation is:
Putting , we get
This equation contains the point (4,12).
In option B, the given equation is:
Putting , we get
This equation does not contain the point (4,12).
In option C, the given equation is:
Putting , we get
This equation contains the point (4,12).
In option D, the given equation is:
Putting , we get
This equation contains the point (4,12).
Only the equation in option B does NOT contain the point (4,12). Therefore, the correct option is B.