Which solid figure does this net represent? A) Eliminate B) square pyramid C) triangular prism D) triangular pyramid

Tito bought a rare album for $68.00 and later sold it for $76.00. What is the percent of increase, rounded to the nearest tenth?

gogolik [260]

70-80=10
hope this help the
68 rounded to the nearest tenth equals 70
and 76 rounded to the nearest tenth equals 80
so if you subtract 80-70=10 Tito increased the percent up to 10 dollars

8 0

3 years ago

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can someone help me figure this out, There are 16 ounces in one pound. A box of nails weighs 4 pounds. How many ounces does the

Alla [95]

The box weighs 64 ounces

4 0

3 years ago

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Use the function below to find F(3)

garik1379 [7]

Answer:

Theanswer is 4/27.

Step-by-step explanation:

given that, F(x) = 4×(1/3)^x

now , F(3)= 4×(1/3)^3 ( putting value of x)

or, F(3) = 4×(1/27)

therefore, F(3)= 4/27... ans

hope it helps..

8 0

3 years ago

WILL GIVE BRAINLIEST! SUPER CONFUSED!!!

kondor19780726 [428]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

⬆ ⬆ ⬆

Low IQR Median High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR is average of 59.3 and 59.6 = 59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

⬆ ⬆ ⬆

Low IQR Median High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

5 0

3 years ago

Find the distance between the points L(7,-1) and M(-2, 4).

zysi [14]

Answer:

The answer is

$\sqrt{106} \: \: \: or \: \: \: 10.3 \: \: \: \: units$

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

L(7,-1) and M(-2, 4)

The distance between them is

$|LM| = \sqrt{ ({7 + 2})^{2} + ( { - 1 - 4})^{2} } \\ = \sqrt{ {9}^{2} + ({ - 5})^{2} } \\ = \sqrt{81 + 25} \\ = \sqrt{106} \: \: \: \: \: \: \: \\ = 10.29563014...$

We have the final answer as

$\sqrt{106} \: \: \: or \: \: \: 10.3 \: \: \: \: units$

Hope this helps you

4 0

2 years ago