<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20%20%7Cm%20%20-%202n%7C%20" id="TexFormula1" title=" \frac{3}{4} |m

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Tatiana [17]

3 years ago

- 2n| " alt=" \frac{3}{4} |m - 2n| " align="absmiddle" class="latex-formula">
if m= -4 and n=6

Mathematics

1 answer:

pishuonlain [190]3 years ago

3 0

Answer:

Step-by-step explanation:

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PLEASE HELP I WILL MARK BRAINLIEST

rewona [7]

Answer:

-4

Step-by-step explanation:

Just add the 2 function

4 0

3 years ago

12. 17g + 149-69 +g =

Kitty [74]

Answer:

12. 18g+80

13. 13x+13

14. 17s

15. 3t

Step-by-step explanation:

On each you just combine the like terms and simplify the equations.

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3 years ago

Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with

skad [1K]

Parameterize S by the vector function

$\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle$

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

$\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle$

The integral of the field over S is then

$\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv$

$\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv$