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3 years ago

Given the equation: (a-c)/(x-a) = m, solve for x.

2 answers:

6 0

We are given with the equation (a-c)/(x-a) = m. In this case, to isolate x, we can use the division, multiplication, addition adn subtraction properties. In this case, Divide the whole equation by m, to give, (a-c)/(x-a)/m = 1. Then multiply by (x-a). Then to isolate x, add a. this results to
x = [(a-c)/m]

REY [17]3 years ago

4 0

If you would like to solve the equation<span> (a - c) / (x - a) = m for x, you can do this using the following steps:

</span><span>(a - c) / (x - a) = m
</span>a - c = m * (x - a)
a - c = mx - ma
mx = a - c + ma
x = (a - c + ma) / m
x = a/m - c/m + a

The correct result would be <span>x = a/m - c/m + a.</span>

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Given the Homogeneous equation x^2ydy+xy^2dx=0, use y=ux, u=y/x and dy=udx+xdu to solve the differential equation. Solve for y.

scZoUnD [109]

Answer:

$y=\frac{C}{x}$ .

Step-by-step explanation:

Given homogeneous equation

$x^2ydy+xy^2dx=0$

$\frac{\mathrm{d}y}{\mathrm{d}x}=-\frac{xy^2}{x^2y}$

Substitute y=ux , $u=\frac{y}{x}$

$\frac{\mathrm{d}y}{\mathrm{d}x}=-\frac{y}{x}$

Now,

$u+x\frac{\mathrm{d}u}{\mathrm{d}x}=\frac{\mathrm{d}y}{\mathrm{d}x}$

$u+x\frac{\mathrm{d}u}{\mathrm{d}x}=-u$

$\frac{\mathrm{d}u}{\mathrm{d}x}=-2u$

$\frac{du}{u}=-\frac{dx}{x}$

Integrating both side we get

lnu=-2lnx+lnC

Where lnC= integration constant

$lnu+ln{x}^2=lnC$

$lnux^2=lnC$

Cancel ln on both side

$ux^2=C$

Substitute $u=\frac{y}{x}$

Then we get

xy=C

$y=\frac{C}{x}$ .

Answer: $y=\frac{C}{x}$ .

8 0

3 years ago

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blondinia [14]

Answer:

Step-by-step explanation:

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3 years ago

Put the following equation in standard form and determine the quadratic, linear, and constant coefficients. -3x2 - 8 = 5x - 7

marusya05 [52]

Answer:

-3x² -5x -1 = 0
-3 (quadratic)
-5 (linear)
-1 (constant)

Step-by-step explanation:

The equation will be in standard form when terms are listed in order of decreasing degree, and the right side of the equation is 0.

<h3>Standard form</h3>

We can subtract the right-side expression from both sides to get standard form.

-3x² -8 -(5x -7) = 5x -7 -(5x -7)

-3x² -8 -5x +7 = 0 . . . . . . . simplify a bit

-3x² -5x -1 = 0 . . . . . . . . . collect terms

The standard form equation can be written ...

-3x² -5x -1 = 0

<h3>Coefficients</h3>

The quadratic coefficient is the coefficient of the term with degree 2. The quadratic coefficient is -3.

The linear coefficient is the coefficient of the term with degree 1. The linear coefficient is -5.

The constant coefficient is the coefficient of the term with no variables. The constant is -1.

<em>Additional comment</em>

We can make the leading coefficient positive by multiplying the equation by -1. This gives ...

3x² +5x +1 = 0

with quadratic, linear, and constant coefficients 3, 5, 1.

This is a legitimate answer to this question. In the case of linear equations, the "standard form" has the constant on the right side of the equal sign, and the leading coefficient is required to be positive. A negative leading coefficient can sometimes lead to errors (when the sign is overlooked), so having a positive leading coefficient is often preferred.

8 0

2 years ago

Simplify the expression<br> 10mn<br> 15m

Afina-wow [57]

Answer:

1) 10mn - 10×m×n

2)15m - 15×m

10×m×n×+15×m

=10mn+15m

factorize

common number(divisor) = 5

5m(2n+3)

5m*2n=10mn

5m*3=15m

4 0

3 years ago

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Dvinal [7]

U have to find the percentage that doesn't have gym memberships between 216. then divide by 8 and then multiply by 5

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3 years ago