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Mumz [18]
3 years ago
5

Last year, Roza put $220 in her saving account that offers 14% increase annually. How much money will be available in her accoun

t next year?
Mathematics
1 answer:
alexgriva [62]3 years ago
8 0
$220+$220*14%=$220+$30.8=$250.8
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Please help this for my pre calculus finals
dsp73

Answer:

a) It will take 17.71 years

b) It will take 17.58 years

c) I will earn $6.60 more in compound continuously

Step-by-step explanation:

a) Lets talk about the compound interest

- The formula for compound interest is A = P (1 + r/n)^(nt)

, Where:

- A = the future value of the investment, including interest

- P = the principal investment amount (the initial deposit)

- r = the annual interest rate (decimal)

- n = the number of times that interest is compounded per unit t

- t = the time the money is invested

* Lets solve the problem

∵ The money deposit is $2000

∵ The rate is 6.25%

∵ The interest is compound quarterly

∵ The future value is $6000

∴ P = 2000

∴ A = 6000

∴ r = 6.25/100 = 0.0625

∴ n = 4

∴ t = ?

∵ A = P (1 + r/n)^(nt)

∴ 6000 = 2000 (1 + 0.0625/4)^4t ⇒ divide both sides by 2000

∴ 3 = (1.015625)^4t ⇒ insert ㏑ for both sides

∴ ㏑(3) = ㏑(1.015625)^4t

∵ ㏑(a)^b = b ㏑(a)

∴ ㏑(3) = 4t ㏑(1.015625) ⇒ divide both sides by ㏑(1.015625)

∴ 4t = ㏑(3)/㏑(1.015625) ⇒ divide both sides by 4

∴ t = [㏑(3)/㏑(1.015625)] ÷ 4 = 17.71

* It will take 17.71 years

b) Lets talk about the compound continuous interest  

- Compound continuous interest can be calculated using the formula:

  A = P e^rt  

- A = the future value of the investment, including interest

- P = the principal investment amount (the initial amount)

- r = the interest rate  

- t = the time the money is invested

* Lets solve the problem

∵ The money deposit is $2000

∵ The rate is 6.25%

∵ The interest is compound continuously

∵ The future value is $6000

∴ P = 2000

∴ A = 6000

∴ r = 6.25/100 = 0.0625

∴ t = ?

∵ A = P e^rt  

∴ 6000 = 2000 e^(0.0625 t) ⇒ divide both sides by 2000

∴ 3 = e^(0.0625 t) ⇒ insert ㏑ to both sides

∴ ㏑(3) = ㏑[e^0.0625 t]

∵ ㏑(e^a) = a ㏑(e) ⇒ ㏑(e) = 1 , then ㏑(e^a) = a

∴ ㏑(3) = 0.0625 t ⇒ divide both sides by 0.0625

∴ t = ㏑(3)/0.0625 = 17.5778

* It will take 17.58 years

c) If t = 5 years

# The compound quarterly:

∵ A = P (1 + r/n)^(nt)

∴ A = 2000 (1 + 0.0625/4)^(4×5)

∴ A = 2000 (1.015625)^20 = $2727.08

# Compound continuously

∵ A = P e^(rt)

∴ A = 2000 e^(0.0625×5) = $2733.68

∴ I will earn = 2733.68 - 2727.08 = $6.60

* I will earn $6.60 more in compound continuously

5 0
3 years ago
What is "The relationship between time and the distance Remaining on a 3 mile walk for someone walking at a steady rate of 2 mph
FromTheMoon [43]

Answer:

Let d be the remaining distance.

Let t be the remaining time.

The standard distance equation is:

d = rt

We are given the rate as 2, so:

d = 2t

At the start of the walk, the remaining distance is 3 miles.

The remaining time is 1.5 hours.

At the end of the walk, the remaining distance is 0 miles.

The remaining time is 0 hours.

A graph of the distance and time would be a continuous, solid line. That's because the walker will be at every distance between 3 and 0 and every time between 1.5 and 0.

Answer:

The graph of this would be a solid line

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8x42+3x59-62=n. What does "n" equal?
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Answer: n=451 8*42+3*59-62=n 336+177-62=n 451=n n=451
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What is 4 percent of 1425
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4% outta 1425 is 57| The amount is 57.
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What is (2/3)^4 <br> does anybody know?
Sveta_85 [38]

Answer:

<h2>16/18</h2>

Step-by-step explanation:

<h2>hopes this helps. Mark as brainlest plz!</h2>
4 0
3 years ago
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