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anygoal [31]
3 years ago
15

One endpoint of a line segment has the coordinates (-5, 12). If the midpoint of the segment is at (2,9), find the

Mathematics
1 answer:
scoray [572]3 years ago
7 0

Answer:

(9, 6)

Step-by-step explanation:

<u>Midpoint formula is:</u>

  • x = (x₁ + x₂)/2
  • y = (y₁ + y₂)/2

<u>Having coordinates of one end- and midpoint </u>(-5, 12) <u>and</u> (2, 9)<u>:</u>

  • x₁ = -5, y₁ = 12
  • x = 2, y = 9

<u>we get the coordinates of the missing endpoint with coordinates</u> (x₂, y₂):

  • x₂ = 2x - x₁ = 2*2 - (-5) = 4 + 5 = 9
  • y₂ = 2y - y₁ = 2*9 - 12 = 18 - 12 = 6

<u>So the missing point is</u>: (9, 6)

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3 years ago
A line is drawn on the coordinate plane that passes through the point (3,-6) and has a slope of 4. The y-intercept of the line i
NISA [10]

Answer:

The y-intercept of the line that passes through the point (3, -6) and which has a slope of 4 is -18.

Step-by-step explanation:

We represent the straight line by using this formula from Analytical Geometry:

y = m\cdot x + b

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

m - Slope, dimensionless.

b - y-Intercept, dimensionless.

Now we clear the y-intercept:

b = y - m\cdot x

If we know that x = 3, y = -6 and m = 4, the y-intercept of the line is:

b = -6 -4\cdot (3)

b = -18

The y-intercept of the line that passes through the point (3, -6) and which has a slope of 4 is -18.

4 0
4 years ago
Which value of x make the equation 1.25(4x − 10) = 7.5 true?
Artemon [7]

Answer:

55.76

Step-by-step explanation:

semoga mambantu

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7 0
3 years ago
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Isabel has ridden 16 miles of a bike course. The course is 80 miles long. What percentage of the course has Isabel ridden so far
OlgaM077 [116]

Answer:

20%

Step-by-step explanation:

Divide 16 by 80 and you get 0.2 as an answer and to get a percent you move the decimal 2 places to the right to fet 20%

7 0
3 years ago
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6. Find the HCF of : (a) 21xy³ and 24x²y² (b) 18ab and 36abc <br>(c) 4p³q²r , -12pr² , 16p²q²r²r²​
Simora [160]

Step-by-step explanation:

<h2><u>➤ </u><u>Solution :-</u></h2><h2>a)</h2>

Given monomials are 21 xy³ and 24x²y²

21 xy³ = 3×7×x×y×y×y

24x²y² = 3×8×x×x×y×y

HCF of 21xy³ and 24x²y²

=> 3×x×y×y

=> 3xy²

HCF of 21xy³ and 24x²y² = 3xy²

<h2>b)</h2>

Given monomials are 18 ab and 36abc

18 ab = 18×a×b

36abc = 2×18×a×b×c

HCF of 18 ab and 36abc

=> 18×a×b

=> 18ab

HCF of 18 ab and 36abc = 18ab

<h2>c)</h2>

Given monomials are 4p³q²r , -12pqr² and 16p²q²r²

4p³q²r = 4×p×p×p×q×q×r

-12pqr² = -3×4×p×q×r×r

16p²q²r² = 4×4×p×p×q×q×r×r

HCF of 4p³q²r , -12pqr² and 16p²q²r²

=> 4×p×q×r

=> 4pqr

HCF of 4p³q²r , -12pqr² and 16p²q²r² = 4pqr

<h2><u>Used Concept :-</u></h2>

→ The HCF of two or more numbers is the highest Common factor

→ The product of least common factors is the HCF of the numbers

3 0
3 years ago
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