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Ugo [173]
2 years ago
8

During a phone call, Beyunka was told of the most recent transactions in her company's business account. There were deposits of

$1, 250 and $3,040.57, three withdrawals of $400 each, and the bank removed two separate $35 penalties to the account that resulted from the bank's errors. Based on the information, how much did the balance of the account change?
Mathematics
1 answer:
Norma-Jean [14]2 years ago
4 0

Answer:

The amount of change in the balance of the account is an increase of $3160.57.

Step-by-step explanation:

i) first deposit is given as $1250

ii) second deposit is given as $3040.57

iii) first withdrawal is given as $400

iv) second withdrawal is given as $400

v) third withdrawal is given as $400

vi) first penalty removed is $35

vii) second penalty removed is $35

viii) therefore the change to the balance is given by

$1250 + $3040.57 - $400 - $400 - $400 + $35 + $35 = $3160.57

viii) Therefore the amount of change in the balance of the account is an increase of $3160.57.

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The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.
valina [46]

Answer:

A sample of 179 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.85}{2} = 0.075

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.075 = 0.925, so Z = 1.44.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

A previous study found that for an average family the variance is 1.69 gallon?

This means that \sigma = \sqrt{1.69} = 1.3

If they are using a 85% level of confidence, how large of a sample is required to estimate the mean usage of water?

A sample of n is needed, and n is found for M = 0.14. So

M = z\frac{\sigma}{\sqrt{n}}

0.14 = 1.44\frac{1.3}{\sqrt{n}}

0.14\sqrt{n} = 1.44*1.3

\sqrt{n} = \frac{1.44*1.3}{0.14}

(\sqrt{n})^2 = (\frac{1.44*1.3}{0.14})^2

n = 178.8

Rounding up

A sample of 179 is needed.

7 0
3 years ago
What percent of students ran the mile in 12 minutes or less?
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41% of students ran in 12 minutes or less.

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14/34 = 0.411 = 41%.
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