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3 years ago

Solve: y=x-4 y=6x-10

Mathematics

1 answer:

KIM [24]3 years ago

3 0

Answer:

x= 6/5 and y= -14/5

Step-by-step explanation:

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Given that IK is a midsegment of AFGH, find GH.

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It’s either C or B but I’m not sure

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3 years ago

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Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

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3 years ago

Find the solutions. Show steps please!

san4es73 [151]

Answer:

x = 0, π/4, π, 7π/4

Step-by-step explanation:

sin(2x) = √2 sin x

Use double angle formula.

2 sin x cos x = √2 sin x

Move everything to one side.

2 sin x cos x − √2 sin x = 0

Factor.

sin x (2 cos x − √2) = 0

Solve.

sin x = 0, cos x = ½√2

x = 0, π/4, π, 7π/4

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2 years ago

assume that a 3 month CD purchased for $2000 pay a simple interest at an annual rate of 10%. How much total interest does it ear

algol [13]

CD = certificate of deposit (an investment)
Interest rate, i = 10% per annum (simple interest)
Principal, P = $2000 (present value)
Period, T = 3 months = 0.25 year

Simple interest formula
Interest earned = Pit
=2000*0.10*0.25
=$50

Balance at maturity (amount that investor gets after three months)
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=$2050

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3 years ago

What is 31×15-11+40 =

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Answer:

494

Step-by-step explanation:

You can use Symbolab to solve equations of all types with explanations

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