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3 years ago

Round 529 to two significant figures

1 answer:

6 0

<span>With the number 529, the 5 is the most significant digit, because it tells us that the number is 500 and something. The 2 is the next most significent digit. After that digit is 9, so we will round it and add 1 onto 2 ( 2 + 1 = 3 ). Finally, 529 to 2 significant figures is: 530 ( and the second significant digit (3) has the overline ).</span>

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A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n indepe

asambeis [7]

Answer:

The binomial mean, or the expected number of successes in n trials, is E(X) = np. The standard deviation is Sqrt(npq), where q = 1-p. The standard deviation is a measure of spread and it increases with n and decreases as p approaches 0 or 1.

Step-by-step explanation:

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4 years ago

Graph the surface of equation z=1/5y^2-3|x|

loris [4]

Answer:

the answer will be 5

Step-by-step explanation:

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3 years ago

The cost of a car rental is $ per day plus per mile. You are on a daily budget of $. Write and solve an inequality to find the

nydimaria [60]

Question:

The cost of a car rental is $42 per day plus 20 cents per mile. you are on a daily budget of $98. write and solve an inequality to find the greatest distance you can drive each day while staying within your budget. use pencil and paper. find 2 other two-step inequalities with the same solutions.

Answer:

(a) The greatest distance is 280 miles

(b) $30 + 0.10 m \le 58$ and $5 m-400 \le 1000$

Step-by-step explanation:

Given

$d = \$42$ ---->daily rate

$m = 20\ cents$ -- amount per mile

$m = \$0.20$ --- in dollars

$Budget = \$98$

Solving (a): Inequality for the scenario

Because you are on a budget, it means that the spending can not exceed $98 (i.e. less than or equal to $98).

So, the inequality is:

$42 * days + 0.20 * miles \le Budget$

Represent days with d, miles with m and substitute 98 for Budget

$42d + 0.20m \le 98$

Because it is daily, then d = 1

$42 * 1+ 0.20 * m \le 98$

$42+ 0.20m \le 98$

Collect like terms

$0.20m \le 98 - 42$

$0.20m \le 56$

$m \le \frac{56}{0.20}$

$m \le 280$

<em>The greatest distance is 280 miles</em>

Solving (b): Two other inequalities with the same solution as: $m \le 280$

To do this, all you need to do is to perform the same operation on both sides of the inequality.

$m \le 280$

Multiply both sides by 0.10

$0.10 * m \le 280 * 0.10$

$0.10 m \le 28$

Add 30 to both sides

$30 + 0.10 m \le 28+30$

$30 + 0.10 m \le 58$ --- equation (1)

Another possible equation is as follows:

$m \le 280$

Multiply both sides by 5

$5 * m \le 280 * 5$

$5 m \le 1400$

Subtract 400 from both sides

$5 m-400 \le 1400-400$

$5 m-400 \le 1000$ --- equation (2)

7 0

3 years ago

Last month, Lana sold 35 necklaces a week at $15 each. However, throughout the month, 6 customers returned their necklaces for a

dalvyx [7]

35 necklaces multiplied by 4 weeks is 140. Multiply 140 by 15, representing the amount of money each necklace costs and you get 2,100. That is the total amount sold, but because the 6 costumers brought their necklaces back, you have to take 6 times 15 to see how much the total returned necklaces cost. That would be $210, so you take $2,100 and subtract $210, and your answer is $1,180. That is the final answer.

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3 years ago

Plz help it’s due tonight i rlly need help thanks

belka [17]

i think we need some more information or something is there any other information that they give you for this question?

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3 years ago