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2 years ago

Solve this riddle: I am an odd number. I an less than 100. The some of my digit is 12. I am a multiple of 15. What number am I?

Mathematics

1 answer:

tiny-mole [99]2 years ago

7 0

The answer to this is 75

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8x-5y=15 <br>6x+4y=43<br>solve the system by any method

Sedbober [7]

Answer:

$x=\frac{275}{62}$ , $y=\frac{127}{31}$

Step-by-step explanation:

<h3>I will use the elimination method.</h3>

We want to make the X's the same:

$24x-15y=45$

$24x+16y=172$

Because the signs of the X's are the same we subtract the 2 equations to make:

(I put the second one on top of the 1st)

$31y=127$

So:

$y=\frac{127}{31}$

Substitute y into either equation 1 or 2:

(I chose equation 1)

$8x-5(\frac{127}{31})=15$

$8x=5(\frac{127}{31}) + 15$

$x=\frac{5(\frac{127}{31})}{8}$

So:

$x=\frac{275}{62}$

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Answer:

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Nina [5.8K]

X= 7/93 or roughly 0.07526...

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Answer:

Step-by-step explanation:

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