3 years ago

What is the value of i^97 - i

Mathematics

1 answer:

Vesna [10]3 years ago

8 0

Answer:

Step-by-step explanation:

i^1 = i

i^2 = - 1

i^3 = i^2 * i = - 1

i^4 = i^2 * i^2 = -1 * -1 = 1

Now the circle just repeats itself. So what you do is find out the remainder of i^97 which you divide by 4. What you get is 24 with a remainder of 1.

So i^97 = i

i - i = 0

The answer is 0

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