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Sergeeva-Olga [200]
3 years ago
11

Given 7x + 2 > 58, which number is not in the solution set?

Mathematics
1 answer:
amid [387]3 years ago
8 0

Answer:

Anything thats not greater than 8 (not including 8 itself)

Step-by-step explanation:

7x+2 > 58

subtract two from either side

7x > 56

Divide 7 from either side

x > 8

Answer: Anything thats not greater than 8 (not including 8 itself)

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Find two numbers if their sum is 91 and the ratio is 6:7.
sammy [17]

Answer:

42:49

Step-by-step explanation:

6x + 7x = 91

13x = 91

x = 7

6 x 7 = 42

7 x 7 = 49

then 42:49

5 0
4 years ago
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What is the formula of x<br>​
tensa zangetsu [6.8K]
Isolate "x" on one side of the algebraic equation by dividing the number that appears on the same side of the equation as part of "x."
4 0
3 years ago
Let u = &lt;3, -1&gt;, v = &lt;-6, -6&gt;. Find 9u + 2v.
Gnom [1K]
9u means you're multiplying 9 into that vector, both components.  Same with the 2v.  9*3 = 27 and 9*-1 = -9, so your new vector u is <27, -9>.  Now let's do v.  2* -6 (twice) = -12, so your new v vector is <-12, -12>.  Add those together now, first components of each and second components of each.  27 + (-12) = 15; -9+(-12)=-21.  So the addition of those gives us a final vector with a displacement of <15, -21>
5 0
3 years ago
WORTH ALOT. Find the amount that results from the investment. 14) $480 invested at 7% compounded quarterly after a period of 9 y
konstantin123 [22]

Answer:

  • $896.36

Step-by-step explanation:

  • Principal = $480
  • Interest rate = 7% compounded
  • Compound number = 4 per year
  • Time = 9 years

<u>Final amount is:</u>

  • 480*(1 + 0.07/4)^(9*4) =
  • 480(1.0175)^36 =
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4 0
3 years ago
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Find the sum of the three smallest positive values of θ such that <img src="https://tex.z-dn.net/?f=4%5Ccos%5E2%282%5Ctheta-%5Cp
Harlamova29_29 [7]

Answer:

∅= 13π/12

Step-by-step explanation:

Solve until you get cos(___) on one side and a value on the other side.

I got cos(2∅-π) = ±√(3)/2

I know that the only cos() value that gives me  ±√(3)/2 are -5π/6, -π/6, and π/6 from looking at the unit circle; those 3 are the smallest value that would give me  ±√(3)/2.

So i solve for what value of 2∅-π would give me -5π/6, -π/6, and π/6

by solving for

2∅₁-π = -5π/6,   2∅₂-π = -π/6,   and 2∅₃-π = π/6

I got ∅₁=π/12, ∅₂=5π/12, ∅₃=7π/12.

The question wanted the sum of the three smallest value so i added it up and got 13π/12.

And thanks for peer review. Good catch on my mistakes.

3 0
4 years ago
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