Given 7x + 2 > 58, which number is not in the solution set?
1 answer:
Answer:
Anything thats not greater than 8 (not including 8 itself)
Step-by-step explanation:
7x+2 > 58
subtract two from either side
7x > 56
Divide 7 from either side
x > 8
Answer: Anything thats not greater than 8 (not including 8 itself)
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Answer:
By Pythagoras theorem
H^2=P^2+B^2
25^2=x^2+24^2
625=x^2 + 576
625-576=x^2
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Hope this helps uhh
Your answer would be 105. Hope this helps!
